(standard form is Ax + By = C)
A line with a slope of 2 and passes a point (4, 1). Please write the equation for this line in standard form.?
Well use point-slope form which is y-[y coordinate]=m(x-[x coordinate])
y-1=2(x-4)
distribute
y-1=2x-4
add 1 to each side
y=2x-3
collect variable terms on one side
y-2x=-3
Reply:I usually use y = mx + b as the standard form, where m is the slope and b is the y-intercept (on the y-axis, where x = 0). If the slope is 2 and it passes through 4,1 it must also pass through 0, -7 (the slope is positive, so from 4,1 it would go left 4 and down 8 to cross the y axis). So the equation would read y = 2x - 7. In your standard form, that would be 2x - y = 7. Substitute your point (4,1) into that equation and it works. The first two answerers' equations do not work.
Reply:y=mx+b
y=2x+1..[this is the standard form]
Reply:Slope : 2 (4,1)
y= 2x+b
1= 2(4)+ b
1= 8+ b
b= -7
Solution: y = 2x + -7
snapdragon2
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment