Math Question.. standard form?

I have to find the equation of a line and the slope is -3/2 and y intercept is 3


so y = -3/2x + 3


how would I put that into standard form? (i think it's ax+by=c.)


x = 6/5


y= 6/5


thanks

Math Question.. standard form?
The standard form equation for a line is


y = mx + b. Where m is the slope and b the y intercept.





y = (-3/2)x + 3 is already the standard form of the equation. Dont worry about the fact that -3/2 is a negative fraction. it simply says that m = -3/2 which is true.





you can multiply throughout by 2 to get rid of the fraction, and rearrange to put the equation in the form ax+by=c but that IS NOT the standard form of the equation for a line.
Reply:It is the standard form... Report It

Reply:3x+2y=6





proof


3x+2y=6


-3x -3x


2y=-3x divid both sides by 2


y=6-3x/2


y=-3x/2+3
Reply:Muultiply y = -3/2x + 3 by 2. That is 2y = -3x + 6.Move the 3x to the other side of the equal. That is 3x+2y=6.
Reply:what's that x and y thing?


Anyways, to put it in standard form you should just multiply everything by 2 to get rid of that denominator and move it around so it would be 3x + 2y = 3
Reply:3x+2y=6
Reply:Wouldn't it = 6? 2y + 3x=6


Last poster i think forgot to mult 3 by 2 as well.


Here... another answer off I'll step it off:


-3/2X +3 = Y


(2)(-3/2X+3)=(2)(Y)


-3X+6 = 2Y


3X+2Y=6





Y=mX + B is 'slope-intercept' form


I posted a good source for Slope-intercept form, Point-Slope Form, and Standard form... last edit i promise :)





Response to additional info:


(1) ax+by+c= 0 is different than (2) ax+by=c because you'd have to subtract c from both sides of equation (2) to get equation (1). In your example problem just subtract 6 from both sides to get 3x+2y-6=0 [a=3,b=2,c=6]

violet