What am i missing in this quadratic standard form q?

the prob is:





3+2x(x-2)=x^2





they want to know what a, b, and c are if i write it out in standard Quad form..... do i have to solve it first?


any help please!

What am i missing in this quadratic standard form q?
3 + 2x(x - 2) = x^2





3 + 2x^2 - 4x = x^2 {distribute the 2x}





x^2 - 4x + 3 = 0 {subtract x^2 from both sides}





a = 1, b = -4, c = 3
Reply:Basically, you just have to write it in the Quadratic Form.





Quadratic form looks like this:


ax^2 + bx + c





So, for this equation,


3+2x(x-2)=x^2


3 + 2x^2 - 4x = x^2


2x^2 - x^2 - 4x + 3 = 0


x^2 - 4x + 3 = 0





So, a = 1, b = -4, and c = 3
Reply:3 + 2x² - 4x = x²





combine terms





2x² - x² - 4x + 3 = 0





x² - 4x + 3 = 0





a = 1, b = -4, c = 3
Reply:You need it in an unfactored form and equated to 0.





3 + 2x(x-2) = x^2





3 + x^2 - 4x = x^2





x^2 - 4x + 3 = 0





Then a=1, b=-4 and c=3

innia