Let Z be a standard normal random variable
P(-c %26lt; Z %26lt; -0.68) = 0.2312
Carry your intermediate computations to at least four decimal places. Round your answer to at least two decimal places
Let Z be a standard normal random variable?
-2.12
The area from 0 to -2.12 is 0.4830
The area from 0 to -0.68 is 0.2517
The difference is 0.2313
innia
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