Standard form??

ok so i kno that standard form is ax + by = c





how woul di find the standard form of the equation of the line that passes through the oints (-5, 4) and (-8, -6)

Standard form??
Hi,


In a few syllables: Use the point-slope form of a linear equation, which is this:


y -y1 = m(x-x1) (Where m is the slope and (x1,y1) is either of the two points. Here's how to use it:


1) First we need the slope:


m = (y2-y1)/(x2-x1) (We can choose either point as (x1,y1)


m = (-6 -4)/(-8- (-5))


=-10/(-3)


= 10/3


So, now we plug that and one of the points, let's choose (-5,4), into


the equation:


y -4 = (10/3)(x- (-5))


y-4 =(10/3)(x +5)


3y-12= 10(x+5) (Multiply by 3)


3y -12 = 10x +50


-10x +3y = 50+12


-10x+3y =62


10x-3y = -62 (The first term must be positive.)





Hope this helps.


FE