Please help with this standard form to quadratic equation!!!!! Ten points for best answer!?

OK, just out of cunfusion





ax^2+bx+c=0 ...standard form





divide all terms by a, so now I have





x^2/a+b/ax+c/a





subract the c/a to the right side so...





x^2+b/ax=-c/a





Now...





x^2+b/ax+(b/2a)^2= -c/a+(b/2a)^2





OK, now here...I think I'm missing a step or two...shouldn't I distribute the exponent through the parenthesis? I just need a step by step process to get from standard form to the quadratic equation. An explanation isn't needed because I can figure out how things are done pretty quickly...I just need the step-by-step instructions!





(x+b/2a)^2=-c/a+(b/2a)^2...





Then...





(x+b/2a)^2=b^2-4ac


-------------


4a^2





Then...





x+b/2a=+/- sqrt b^2-4ac/4a^2





Then quadratic form!





I'm sure you do know that!











Thanks so much!

Please help with this standard form to quadratic equation!!!!! Ten points for best answer!?
NOOOOO!!! I had enough math today!!!!!!!! * hides under bed wielding a Popsicle*
Reply:hello!


dude you don't have to divide everything by "a" anymore..


the equation goes like:





ax^2 + bx + c = 0





a, b and c are constants:whole numbers


they will be used in order to get your perfect square or use them in a quadratic formula:





ex:


2x^2 - 4x + 1= this is a perfect square


(2x -1) ( 2x -1)





using this in the quadratic equation, you dont have to divide everything by 2,


jsut substitute the values:





-b +/- sqre rt of(b^2 - 4ac)


------------------------------------


2a





hope this helps!
Reply:I wish I was smart enough to figure this out but you did miss an "x"
Reply:420.
Reply:you miss the x in the middle term


ax^2 + bx = -c . . . . orig formula


x^2 + b/a x = -c/a . . . . divide by a


3rd term = (b/a x ) / (2x) = b/(2a) . . . square this and add to both


x^2 + b/a x + [b/(2a)]^2 = -c/a + [b/(2a)]^2


[ x + b/(2a) ]^2 = -c/a + b^2/(4a^2). . . square root both sides


x + b/(2a) = sqr( -c/a + b^2/(4a^2))


x = - b / (2a) +- sqr[ b^2/(4a^2) - c/a ] . . . . change position


x = - b / (2a) +- sqr[ (b^2 - 4ac) / (4a^2) ] . . common denominator 4a^2


x = [- b / (2a) +- sqr[ (b^2 - 4ac) ] 2a

snapdragon2