How do you solve a standard normal value?

can anyone solve this and tell me how you solved it? THANK YOU





Let z be a standard normal random variable. Determine the Value of C





P(-C%26lt; Z%26lt; C)=.9312





both less than signs are suppose to be less than or equal to..I couldn't put a line under the signs.

How do you solve a standard normal value?
A "standard" normal value just means that the mean is 0 and the standard deviation is 1. You can adjust any normal distribution by subtracting the mean and dividing by the std. dev.





z = (x - mu)/sigma





Since the distribution is symmetric about 0, the probability of being %26gt; - C is the same as being %26lt; C, so you only need to find P( Z %26lt; C ) = .4656. You look up the value .4656 in a table and find out the value for C.





It can be a little tricky looking it up. You may need to play around with the 0.9312 some more, but that's the idea. :-). Just keep in mind the picture of what you're trying to find. The values of +/- C that accounts for 93.12% of the normal distribution.