Sunday, August 2, 2009

A line with a slope of 2 and passes a point (4, 1). Please write the equation for this line in standard form.?

(standard form is Ax + By = C)

A line with a slope of 2 and passes a point (4, 1). Please write the equation for this line in standard form.?
Well use point-slope form which is y-[y coordinate]=m(x-[x coordinate])





y-1=2(x-4)


distribute


y-1=2x-4


add 1 to each side


y=2x-3


collect variable terms on one side


y-2x=-3
Reply:I usually use y = mx + b as the standard form, where m is the slope and b is the y-intercept (on the y-axis, where x = 0). If the slope is 2 and it passes through 4,1 it must also pass through 0, -7 (the slope is positive, so from 4,1 it would go left 4 and down 8 to cross the y axis). So the equation would read y = 2x - 7. In your standard form, that would be 2x - y = 7. Substitute your point (4,1) into that equation and it works. The first two answerers' equations do not work.
Reply:y=mx+b


y=2x+1..[this is the standard form]
Reply:Slope : 2 (4,1)





y= 2x+b





1= 2(4)+ b





1= 8+ b





b= -7





Solution: y = 2x + -7

snapdragon2

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