For example if i have to create a project for calculating wages of employee in c# console application.What is the standard method to write the program?Like creating Constructors........,methods...
What is the procedure for writing a standard program or a project?
define the objects (employee, payscale, etc.)
implement the objects as classes
write a program to use those classes to create your payroll program.
BTW - your technical lead should be giving you these directions
Friday, July 31, 2009
A random sample of 121 checking accounts at a bank showed an average daily balance of $280. the standard?
deviation of the population is know to be $66.
a. Is it necessary to know anything about the shape of the distribution of the account balances in order to make an interval estimate of the mean of all the account balances? Explain.
b. Find the standard error of the mean.
c. Give a point estimate of the population mean.
d. Construct a 80% confidence interval estimates for the mean.
e. Construct a 95% confidence interval for the mean.
A random sample of 121 checking accounts at a bank showed an average daily balance of $280. the standard?
you would need to know whether the distribution was a bell-shaped curve (normal distribution).
a. Is it necessary to know anything about the shape of the distribution of the account balances in order to make an interval estimate of the mean of all the account balances? Explain.
b. Find the standard error of the mean.
c. Give a point estimate of the population mean.
d. Construct a 80% confidence interval estimates for the mean.
e. Construct a 95% confidence interval for the mean.
A random sample of 121 checking accounts at a bank showed an average daily balance of $280. the standard?
you would need to know whether the distribution was a bell-shaped curve (normal distribution).
Easy STATISTICS Standard Deviation Question, That Has For Some Reason Left Me Stumped :) HELP!?
Hi, I have a question that I'm just a bit confused on. I don't have the formula, so I don't understand what they are doing. I do have the right answer though. If you could explain this, that would be great!!!
A study shows that 20% of all births take place by C-section each year.
IN a random sample of 1000 births, how many on average will take place by C-section?
Answer: 200 (I understand this :)
What is the standard deviation of the number of C-section births in a sample of 1000?
Answer: 12.6 (How do I find this?)
Use your answers parts a and b to form an interval, within two standard deviations, that contians the number of C-section births in a sample of 1000.
Answer: (175, 225) (How? I thought you would just take the standard deviation and add and subtract it to the average)
THANK YOU! :)
Easy STATISTICS Standard Deviation Question, That Has For Some Reason Left Me Stumped :) HELP!?
Your situation here is an example of a binomial distribution, if you hadn't realized this already. The number of C-sections is a binomial random variable X. The standard deviation = the square root of (np(1-p)). In this case, sample size n is 1000, and probability p is 0.2. Putting these into the equation gives you a standard deviation of 12.6491, which matches your answer. Adding and subtracting two of these std. devs from your mean of 200 will give you an interval of roughly (175, 225.) Hope this helped...
A study shows that 20% of all births take place by C-section each year.
IN a random sample of 1000 births, how many on average will take place by C-section?
Answer: 200 (I understand this :)
What is the standard deviation of the number of C-section births in a sample of 1000?
Answer: 12.6 (How do I find this?)
Use your answers parts a and b to form an interval, within two standard deviations, that contians the number of C-section births in a sample of 1000.
Answer: (175, 225) (How? I thought you would just take the standard deviation and add and subtract it to the average)
THANK YOU! :)
Easy STATISTICS Standard Deviation Question, That Has For Some Reason Left Me Stumped :) HELP!?
Your situation here is an example of a binomial distribution, if you hadn't realized this already. The number of C-sections is a binomial random variable X. The standard deviation = the square root of (np(1-p)). In this case, sample size n is 1000, and probability p is 0.2. Putting these into the equation gives you a standard deviation of 12.6491, which matches your answer. Adding and subtracting two of these std. devs from your mean of 200 will give you an interval of roughly (175, 225.) Hope this helped...
A line with a slope of 2 and passes a point (4, 1). Please write the equation for this line in standard form.?
A line with a slope of 2 and passes a point (4, 1). Please write the equation for this line in standard form. (standard form is Ax + By = C)
A line with a slope of 2 and passes a point (4, 1). Please write the equation for this line in standard form.?
First use slope intercept form-
y=mx+b, where m is the slope and b is the y intercept
y=2x+b
plug in the point-
1=2(4)+b
1=8+b
b=-7
Thus,
y=2x-7
Move the numbers around
2x-y-7=0
2x-y=7
=)
Reply:First things first. We have a point and a slope, so we'll start with point-slope form and then try to transfer it to standard form.
y-ysub1=m(x-xsub1)
y-1=2(x-4)
Distribute
y-1=2x-8
Now, while it's the opposite of Ax+By=C, we'll move the variables to the right, and the constant to the left. We'll flip later, but the positive coefficent of x is needed for standard form.
-1-(-8)=2x-y
Flip and add
2x-y=7
Reply:I think it may be -2x + y = -7 but I'm not sure.
Reply:y=2x+4
if thats the y-intercept form then all u have to do is make it equal to zero.
-2x -4 + y =0
hope i helped :)
avender
A line with a slope of 2 and passes a point (4, 1). Please write the equation for this line in standard form.?
First use slope intercept form-
y=mx+b, where m is the slope and b is the y intercept
y=2x+b
plug in the point-
1=2(4)+b
1=8+b
b=-7
Thus,
y=2x-7
Move the numbers around
2x-y-7=0
2x-y=7
=)
Reply:First things first. We have a point and a slope, so we'll start with point-slope form and then try to transfer it to standard form.
y-ysub1=m(x-xsub1)
y-1=2(x-4)
Distribute
y-1=2x-8
Now, while it's the opposite of Ax+By=C, we'll move the variables to the right, and the constant to the left. We'll flip later, but the positive coefficent of x is needed for standard form.
-1-(-8)=2x-y
Flip and add
2x-y=7
Reply:I think it may be -2x + y = -7 but I'm not sure.
Reply:y=2x+4
if thats the y-intercept form then all u have to do is make it equal to zero.
-2x -4 + y =0
hope i helped :)
avender
What is the pressure at standard temperature?
A gas has a pressure of 0.370 atm at 50.0 °C. What is the pressure at standard temperature?
What is the pressure at standard temperature?
the equation is (starting pressure)/(starting temperature) = (ending pressure)/(ending temperature)
Substitute in:
0.370 atm / 323 K = X atm / 273 K, where X is ending pressure
0.370 atm * 273 K / 323 K = X atm
0.313 atm = X (ending pressure)
Reply:Gay Lussac's Law.
"The absolute pressure of a given mass of gas is directly proportional to is temperature at constant volume".
P1T2 = P2T1
P1 = 0.370atm...T2 = 273K
P2 = ?...............T1 = 323K
P2 = (0.370 x 273) ÷ 323
P2 = 101.01 ÷ 323
P2 = 0.313atm = Final pressure.
Reply:Do your own homework.
What is the pressure at standard temperature?
the equation is (starting pressure)/(starting temperature) = (ending pressure)/(ending temperature)
Substitute in:
0.370 atm / 323 K = X atm / 273 K, where X is ending pressure
0.370 atm * 273 K / 323 K = X atm
0.313 atm = X (ending pressure)
Reply:Gay Lussac's Law.
"The absolute pressure of a given mass of gas is directly proportional to is temperature at constant volume".
P1T2 = P2T1
P1 = 0.370atm...T2 = 273K
P2 = ?...............T1 = 323K
P2 = (0.370 x 273) ÷ 323
P2 = 101.01 ÷ 323
P2 = 0.313atm = Final pressure.
Reply:Do your own homework.
What is the procedure for writing a standard program or a project?
What is the procedure for writing a standard program or a project?
For example if i have to create a project for calculating wages of employee in c# console application.What is the standard method to write the program?Like creating Constructors........,methods.....
What is the procedure for writing a standard program or a project?
Have no idea!!
For example if i have to create a project for calculating wages of employee in c# console application.What is the standard method to write the program?Like creating Constructors........,methods.....
What is the procedure for writing a standard program or a project?
Have no idea!!
For those of you who have had numerous partners/relationships, is it b/c you have "lower standards" or
you happen to encounter wonderful people where you live? Please don't be offended when I mean "lower standards", I just mean that you are not very particular when looking for someone. I have never found someone "good enough" in my 22 years.
For those of you who have had numerous partners/relationships, is it b/c you have "lower standards" or
I grew up in the 1960's and 1970's, there was not a lot of incurable std's, birth control actually worked very reliably for the first time in history, and frankly, some of us used a lot of alcohol and it tends to cloud your judgement. Since then, I've had a limited number of partners since I was in a relationship (the partners occured after the break-up) and I don't drink. After 15 years in a relationship, I went a bit sex crazy, but quickly calmed down. I'm not religious, and obviously have different standards than you do. To each their own.
Reply:you have GOT to have an open mind. i think thats what you meant by "lower standards."
what you are doing is a form of self protection. you are using your "too good for you" status to protect you from ever being exposed to love and ever getting hurt. you fooled a lot of people, but you didn't fool me.
Reply:you know thats kinda offensive....
who a person sleeps with really in the long run...isnt your business.
I found my someone special when I was 16...took me 8 years but he is my husband now...so Phhhhhhhh :-D~
Reply:Some people meet the right person and fall in love sooner, maybe in their teens, for others it takes longer. I didn't meet a man who was right for me until well into my twenties. Just the way it works out sometimes.
I guess some people can separate love and sex completely... I can't, which is why I've had very few partners. But if you can, then it's probably more about the sex than the person. Sex on it's own means nothing to me.
I don't think standards are high or low, just different. Our expectations of first-time sex are different. If you think waiting will help to fulfil yours, then stick with it.
Reply:Mine were learning experiences. I am married now. Would my previous relationships have met my current standards? Hell no. Does that mean I set my standards too low to begin with? Perhaps a little bit, but I was also younger, therefore less mature myself. My first relationship was when I was about 13. It was puppy love, a high school thing. Was it perfect? No, but I did learn a lot of things about myself and what I need in a relationship. I would rather start with my standards a little bit too low than too high. If you have an idea of what the perfect guy is like, you probably won't find him because you might see 98% perfect guy and not realize that that is pretty darn good. Having more than one relationship helps you realize what is actually important and was is just a bit of a preference.
Reply:Well, when I was young I don't think I had very high standards, I would sleep with anyone who I found reasonably attractive, if they asked me. It never occured to me not to.
And when you talk about not having found anyone good enough in your 22 years, if you are only 22 then i trust that you have not actually been looking for somone to sleep with for all of that time.
Reply:i think some do have lower standards..
and i think some ppl have good intentions...but they just keep ending up with complete idiots...
i feel sorry for the second group..and i hope they end up finding someone worthy of them.
Reply:When I was 22 I had found only one and, yes, he was wonderful. We met when i was 13 and he 14- he died a few months before I turned 22. So our nearly 8 years together gave us something that I remember fondly.
A few years later before I married I had found a couple of more gentlemen who met my standards. I am very particular but also human. Humans are supposed to form relationships and I find nothing seedy about sex. I am not "too good" to reach out for human companionship.
Reply:I promise not to take offense to yours if you don't to mine.
You don't have a standard until you've had at least one relationship. It's just the definition of the word is a basis for comparison. If you don't have one then you don't have a standard.
Standard: a basis for comparison; a reference point against which other things can be evaluated; "the schools comply with federal standards"; "they set the ...
Reply:I found people but very few and it is not a conscious decision I just cannot force myself to feel attraction were none exists.
Reply:I think you should have used something other than 'lower standards'.
Anyways, honestly, there were about 10 guys who I had some kind of non-serious relationship with. I found the guy that I knew was worth sticking with when I was 20.
At 20, I found the type of guy that I figured out that I was looking for. He was not perfect obviously, but we were compatible and he is great and wonderful.
Sometimes it's also about trial and error.. dating new guys.. seeing what kind of person you want to be with. You get closer and closer to the guy that's right for you every time, because you have more specific 'requirements' if you will.. i.e. I met a guy who was my religion, nice, gentlemanly.. but he wasn't FUNNY, which I realized that I needed.
You need to realize that your language is offensive.. next time say it in a different wayor don't say it.
Reply:I'm the same way, picky.
And you live in Manhattan so no wonder it's hard to find someone
Reply:No, it's not offensive. I was lonely. I wish I had waited. Once you're married, you realize that you don't need to "practice" before marriage to get better at relationship stuff. Only marriage can teach you how to be married. Each person is unique, and learning how to be guy "A"'s partner does not mean you're going to be any better at being guy "B"'s partner.
My high school boyfriend was a very nice boy, but we realized that we wanted different things out of life. It never really occurred to me to wait for a guy who wanted to get married and had the same goals and values as I did. I was dealing with my parent's divorce and, as the only child still in the house, I was alone all the time. My actions were fairly G-rated compared to my friends. Still, I wish I had waited.
Reply:Maybe you're too choosy. I don't mean that offensively, but if you expect perfection, you're never going to find anyone who's "good enough". I think most people decide what traits are important to them, and overlook flaws that aren't crucial, such as being a little overweight or too short or not funny or cool enough.
I know people, guys mostly, who whine endlessly about being single, but then turn down any girl who isn't a supermodel. These guys are by far not perfect-looking, or rich, or anything but ordinary. But they still expect perfection in their lovers. This is what I strive not to be. I consider myself to have very high standards, but I try to be picky about things that matter. Like how well we get along, how good the conversation is, how intelligent and interesting they are. Beyond that, flaws are something I expect, and can work with.
Reply:am just luved up, don't know who you hang around but i would never lower my standards
Reply:Nope, not lower standards, I just like sex... it feels good, it is fun, and I (and I'm sure this will get me in trouble) don't think it's the end-all-be-all to give away your v-card.
Reply:Reading between the lines I'm wondering if there is a percent of you that's jealous of such people. Is that true?
For those of you who have had numerous partners/relationships, is it b/c you have "lower standards" or
I grew up in the 1960's and 1970's, there was not a lot of incurable std's, birth control actually worked very reliably for the first time in history, and frankly, some of us used a lot of alcohol and it tends to cloud your judgement. Since then, I've had a limited number of partners since I was in a relationship (the partners occured after the break-up) and I don't drink. After 15 years in a relationship, I went a bit sex crazy, but quickly calmed down. I'm not religious, and obviously have different standards than you do. To each their own.
Reply:you have GOT to have an open mind. i think thats what you meant by "lower standards."
what you are doing is a form of self protection. you are using your "too good for you" status to protect you from ever being exposed to love and ever getting hurt. you fooled a lot of people, but you didn't fool me.
Reply:you know thats kinda offensive....
who a person sleeps with really in the long run...isnt your business.
I found my someone special when I was 16...took me 8 years but he is my husband now...so Phhhhhhhh :-D~
Reply:Some people meet the right person and fall in love sooner, maybe in their teens, for others it takes longer. I didn't meet a man who was right for me until well into my twenties. Just the way it works out sometimes.
I guess some people can separate love and sex completely... I can't, which is why I've had very few partners. But if you can, then it's probably more about the sex than the person. Sex on it's own means nothing to me.
I don't think standards are high or low, just different. Our expectations of first-time sex are different. If you think waiting will help to fulfil yours, then stick with it.
Reply:Mine were learning experiences. I am married now. Would my previous relationships have met my current standards? Hell no. Does that mean I set my standards too low to begin with? Perhaps a little bit, but I was also younger, therefore less mature myself. My first relationship was when I was about 13. It was puppy love, a high school thing. Was it perfect? No, but I did learn a lot of things about myself and what I need in a relationship. I would rather start with my standards a little bit too low than too high. If you have an idea of what the perfect guy is like, you probably won't find him because you might see 98% perfect guy and not realize that that is pretty darn good. Having more than one relationship helps you realize what is actually important and was is just a bit of a preference.
Reply:Well, when I was young I don't think I had very high standards, I would sleep with anyone who I found reasonably attractive, if they asked me. It never occured to me not to.
And when you talk about not having found anyone good enough in your 22 years, if you are only 22 then i trust that you have not actually been looking for somone to sleep with for all of that time.
Reply:i think some do have lower standards..
and i think some ppl have good intentions...but they just keep ending up with complete idiots...
i feel sorry for the second group..and i hope they end up finding someone worthy of them.
Reply:When I was 22 I had found only one and, yes, he was wonderful. We met when i was 13 and he 14- he died a few months before I turned 22. So our nearly 8 years together gave us something that I remember fondly.
A few years later before I married I had found a couple of more gentlemen who met my standards. I am very particular but also human. Humans are supposed to form relationships and I find nothing seedy about sex. I am not "too good" to reach out for human companionship.
Reply:I promise not to take offense to yours if you don't to mine.
You don't have a standard until you've had at least one relationship. It's just the definition of the word is a basis for comparison. If you don't have one then you don't have a standard.
Standard: a basis for comparison; a reference point against which other things can be evaluated; "the schools comply with federal standards"; "they set the ...
Reply:I found people but very few and it is not a conscious decision I just cannot force myself to feel attraction were none exists.
Reply:I think you should have used something other than 'lower standards'.
Anyways, honestly, there were about 10 guys who I had some kind of non-serious relationship with. I found the guy that I knew was worth sticking with when I was 20.
At 20, I found the type of guy that I figured out that I was looking for. He was not perfect obviously, but we were compatible and he is great and wonderful.
Sometimes it's also about trial and error.. dating new guys.. seeing what kind of person you want to be with. You get closer and closer to the guy that's right for you every time, because you have more specific 'requirements' if you will.. i.e. I met a guy who was my religion, nice, gentlemanly.. but he wasn't FUNNY, which I realized that I needed.
You need to realize that your language is offensive.. next time say it in a different wayor don't say it.
Reply:I'm the same way, picky.
And you live in Manhattan so no wonder it's hard to find someone
Reply:No, it's not offensive. I was lonely. I wish I had waited. Once you're married, you realize that you don't need to "practice" before marriage to get better at relationship stuff. Only marriage can teach you how to be married. Each person is unique, and learning how to be guy "A"'s partner does not mean you're going to be any better at being guy "B"'s partner.
My high school boyfriend was a very nice boy, but we realized that we wanted different things out of life. It never really occurred to me to wait for a guy who wanted to get married and had the same goals and values as I did. I was dealing with my parent's divorce and, as the only child still in the house, I was alone all the time. My actions were fairly G-rated compared to my friends. Still, I wish I had waited.
Reply:Maybe you're too choosy. I don't mean that offensively, but if you expect perfection, you're never going to find anyone who's "good enough". I think most people decide what traits are important to them, and overlook flaws that aren't crucial, such as being a little overweight or too short or not funny or cool enough.
I know people, guys mostly, who whine endlessly about being single, but then turn down any girl who isn't a supermodel. These guys are by far not perfect-looking, or rich, or anything but ordinary. But they still expect perfection in their lovers. This is what I strive not to be. I consider myself to have very high standards, but I try to be picky about things that matter. Like how well we get along, how good the conversation is, how intelligent and interesting they are. Beyond that, flaws are something I expect, and can work with.
Reply:am just luved up, don't know who you hang around but i would never lower my standards
Reply:Nope, not lower standards, I just like sex... it feels good, it is fun, and I (and I'm sure this will get me in trouble) don't think it's the end-all-be-all to give away your v-card.
Reply:Reading between the lines I'm wondering if there is a percent of you that's jealous of such people. Is that true?
What are these new A/C sockets?
I've just got my house rewired. In addition to the standard, three square pin A/C sockets, the electrician has put in smaller, three round pin sockets. Does anyone know what these are? I've never seen them before.
What are these new A/C sockets?
They are 5A sockets which take 5A plugs and are soley used for lights, usually found in the bedrooms and intended for use with bed-side lights.
Reply:the round sockets used to be used for lighting circuits (you are living in the UK yeah?) though these kinda phased themselves out years ago.
they will still work mind, but are normally rated to specific appliances. Ask your electrician to confirm what he's done.
Reply:They are either 2a or 5a sockets, (as has been said) for table lamps to BS546. http://www.toolstation.com/index.html?co...
You'll need a plug to match. http://www.toolstation.com/search.html?s...
Reply:THESE ARE MOST LIKELY 5 AMP SOCKETS BUT COULD ALSO BE 2 AMP, EFECTIVELY THE SAME THING. THEY ARE SOCKETS FOR LIGHTING AND GENERALY CONTROLED LOCALY VIA A LIGHT SWITCH, FOR SIDE LAMPS ETC... THE REASON FOR THE ROUND PIN IS TO AVOID ACCIDENTAL USAGE IE PLUGING IN A HOOVER AS THESE SOCKETS ARE FUSED MUCH SMALLER THAN REGULAR SOCKETS 10A AS OPPOSED TO 20A . AND ARE NOT OUT DATED AS SUGGESTED BY A PREVIOUS .... BUT EXTREMELY POPULAR IN MODERN DAY HOUSE HOLDS..
Reply:They are 5Amp circuits and use a different plug so you dont plug say an Iron in by mistake. They are usually for Table lamps etc
Reply:Telephone connection I think !!!
violet
What are these new A/C sockets?
They are 5A sockets which take 5A plugs and are soley used for lights, usually found in the bedrooms and intended for use with bed-side lights.
Reply:the round sockets used to be used for lighting circuits (you are living in the UK yeah?) though these kinda phased themselves out years ago.
they will still work mind, but are normally rated to specific appliances. Ask your electrician to confirm what he's done.
Reply:They are either 2a or 5a sockets, (as has been said) for table lamps to BS546. http://www.toolstation.com/index.html?co...
You'll need a plug to match. http://www.toolstation.com/search.html?s...
Reply:THESE ARE MOST LIKELY 5 AMP SOCKETS BUT COULD ALSO BE 2 AMP, EFECTIVELY THE SAME THING. THEY ARE SOCKETS FOR LIGHTING AND GENERALY CONTROLED LOCALY VIA A LIGHT SWITCH, FOR SIDE LAMPS ETC... THE REASON FOR THE ROUND PIN IS TO AVOID ACCIDENTAL USAGE IE PLUGING IN A HOOVER AS THESE SOCKETS ARE FUSED MUCH SMALLER THAN REGULAR SOCKETS 10A AS OPPOSED TO 20A . AND ARE NOT OUT DATED AS SUGGESTED BY A PREVIOUS .... BUT EXTREMELY POPULAR IN MODERN DAY HOUSE HOLDS..
Reply:They are 5Amp circuits and use a different plug so you dont plug say an Iron in by mistake. They are usually for Table lamps etc
Reply:Telephone connection I think !!!
violet
How to open an include file in c program?
This C program starts with #include %26lt;stdio.h%26gt;. This line includes the "standard I/O library" into your program. The standard I/O library lets you read input from the keyboard (called "standard in"), write output to the screen (called "standard out"), process text files stored on the disk, and so on. It is an extremely useful library. C has a large number of standard libraries like stdio, including string, time and math libraries.
How to open an include file in c program?
Did you want to just look at the header file itself? If so, their location is dependent on the the operating system and the compiling system that you are working with.
Like with GCC on a *nix system, you can usually find them here.
/usr/local/include
/usr/lib/gcc-lib/target/version/includ...
/usr/target/include
/usr/include
Reply:go to the com.
Reply:Ummm... did you notice that you answered your own question? Have you perhaps got other things about this whole "C" programming gig you would like to know more about?
How to open an include file in c program?
Did you want to just look at the header file itself? If so, their location is dependent on the the operating system and the compiling system that you are working with.
Like with GCC on a *nix system, you can usually find them here.
/usr/local/include
/usr/lib/gcc-lib/target/version/includ...
/usr/target/include
/usr/include
Reply:go to the com.
Reply:Ummm... did you notice that you answered your own question? Have you perhaps got other things about this whole "C" programming gig you would like to know more about?
How do i write an equation of a line in standard form that has a slope of -3/5 and passes through (2,1)?
i no standard form is Ax+By=C, but how do i make it happen?
How do i write an equation of a line in standard form that has a slope of -3/5 and passes through (2,1)?
hey dont worry i ll help u out......
given pt. is (2,1) and the slope is -3/5.
so the eqn. of the line is-
(y-1)=-3/5(x-2)
solve it and u ll get,
3x+5y=11 (answer)
Reply:1 = (-3/5)(2) + b.
b = 11/5.
Equation in slope-intercept form: y = -3x/5 + 11/5.
Equation in standard form: 3x + 5y = 11.
-John
Reply:gradient = -3/5 and point (2,1)
use equation y-y1=m(x-x1)
where m is the gradient and point (2,1) is( x1,y1)
therefore substitute in eqn:
(y-1)=-3/5(x-2)
y-1=3/5x-6/5
y=3/5x-1/5
5y=3x-1
Reply:You write
y = (-3/5) (x) + b
and determine b from the given point (2, 1) on the line; then rewrite the line equation given above with b replaced.
If you want a standard form with all variable terms on the left and a constant on the right, then you can juggle the above expression (after determining b) and get to that form.
Reply:start with point-slope form
(y-1) = (-3/5)(x-2)
multiply through by 5
5y - 5 = -3x + 6
add 5 to both sides
5y = -3x + 11
add 3x to both sides
5y + 3x = 11
Reply:Us the point-slope form
y - 1 = (-3/5)(x - 2)
Multiply both sides by 5
5y - 5 = -3(x - 2)
Multiply through the -3
5y - 5 = -3x + 6
Add 3x to both sides
3x + 5y - 5 = -3x + 3x + 6
3x + 5y - 5 = 6
Add 5 to both sides
3x + 5y - 5 + 5 = 6 + 5
3x + 5y = 11
Reply:(2,1) are the x and y coordinates. (x,y)
Equation of a line is in the form:
y= mx + c, where,
m is the gradient or slope of the line
c is the y-intercept
"m" is known as -3/5
Next find y-intercept.
substitue into the general form: y = mx+c
we use co-ordinate (2, 1)
1 = -3/5 (2) + c
5/5 = -6/5 + c
c = 11/5
Now, we have m = -3/5 and c = 11/5
Hence, general equation of the line is
y = -3/5x + 11/5
multiply 5 on both sides:
5y = -3x +11
Re-arranging equation:
3x + 5y = 11
How do i write an equation of a line in standard form that has a slope of -3/5 and passes through (2,1)?
hey dont worry i ll help u out......
given pt. is (2,1) and the slope is -3/5.
so the eqn. of the line is-
(y-1)=-3/5(x-2)
solve it and u ll get,
3x+5y=11 (answer)
Reply:1 = (-3/5)(2) + b.
b = 11/5.
Equation in slope-intercept form: y = -3x/5 + 11/5.
Equation in standard form: 3x + 5y = 11.
-John
Reply:gradient = -3/5 and point (2,1)
use equation y-y1=m(x-x1)
where m is the gradient and point (2,1) is( x1,y1)
therefore substitute in eqn:
(y-1)=-3/5(x-2)
y-1=3/5x-6/5
y=3/5x-1/5
5y=3x-1
Reply:You write
y = (-3/5) (x) + b
and determine b from the given point (2, 1) on the line; then rewrite the line equation given above with b replaced.
If you want a standard form with all variable terms on the left and a constant on the right, then you can juggle the above expression (after determining b) and get to that form.
Reply:start with point-slope form
(y-1) = (-3/5)(x-2)
multiply through by 5
5y - 5 = -3x + 6
add 5 to both sides
5y = -3x + 11
add 3x to both sides
5y + 3x = 11
Reply:Us the point-slope form
y - 1 = (-3/5)(x - 2)
Multiply both sides by 5
5y - 5 = -3(x - 2)
Multiply through the -3
5y - 5 = -3x + 6
Add 3x to both sides
3x + 5y - 5 = -3x + 3x + 6
3x + 5y - 5 = 6
Add 5 to both sides
3x + 5y - 5 + 5 = 6 + 5
3x + 5y = 11
Reply:(2,1) are the x and y coordinates. (x,y)
Equation of a line is in the form:
y= mx + c, where,
m is the gradient or slope of the line
c is the y-intercept
"m" is known as -3/5
Next find y-intercept.
substitue into the general form: y = mx+c
we use co-ordinate (2, 1)
1 = -3/5 (2) + c
5/5 = -6/5 + c
c = 11/5
Now, we have m = -3/5 and c = 11/5
Hence, general equation of the line is
y = -3/5x + 11/5
multiply 5 on both sides:
5y = -3x +11
Re-arranging equation:
3x + 5y = 11
How do you find slope given an equation in standard form?
Standard form is Ax+By=C
I have 4x+3y=2
How do I find the slope?
How do you find slope given an equation in standard form?
The slope of ANY equation written in standard form is -A/B. Your teacher probably didn't tell you this so now you can amaze him when he sees how fast you can find the slope.
So in this equation, A = 4, B = 3. Plug it in, and you will get -(4/3).
Reply:You will need to graph it first
y2-y1/x2-x1
Reply:Rearrange.
4x + 3y = 2 (The actual equation)
3y = -4x + 2 (add 4x)
y = -4/3x +2/3 (divide by 3)
The slope is -4/3
Reply:You put that equation in slope-form intercept (y=mx+b).Solve for y in other words
4x+3y=2 First you minus 4x by both sides
-4x___-4x Then divide 3 by both sides to get y by
3y= -4x+2 Itself
3 3
y= -4/3x+2
x is the slope which is -4/3
Reply:-A/B
Reply:Slope is -4/3, I think.
A slope formula we were tought is y=mx + b where m always stands for slope. In this case, I transformed the formula Ax+By=C into By= -Ax+C. Since you need to get rid of the numerical coefficient of y, transpose B by dividing both sides by it.
From 3y= -4x+2, it will now look like y=(-4x+2)/3 or y=(-4x)/3 + 2/3 in simplest form. Since the slope is the numerical coefficient of x, -4/3 will then be the slope.
Reply:The easiest way to remember what to do is just to remember that the slope is the y-intercept
Reply:4x + 3y = 2
y = -4/3 x + 2/3
the equation is y = mx + b; where m is the slope..
therefore, -4/3 is your slope...
I have 4x+3y=2
How do I find the slope?
How do you find slope given an equation in standard form?
The slope of ANY equation written in standard form is -A/B. Your teacher probably didn't tell you this so now you can amaze him when he sees how fast you can find the slope.
So in this equation, A = 4, B = 3. Plug it in, and you will get -(4/3).
Reply:You will need to graph it first
y2-y1/x2-x1
Reply:Rearrange.
4x + 3y = 2 (The actual equation)
3y = -4x + 2 (add 4x)
y = -4/3x +2/3 (divide by 3)
The slope is -4/3
Reply:You put that equation in slope-form intercept (y=mx+b).Solve for y in other words
4x+3y=2 First you minus 4x by both sides
-4x___-4x Then divide 3 by both sides to get y by
3y= -4x+2 Itself
3 3
y= -4/3x+2
x is the slope which is -4/3
Reply:-A/B
Reply:Slope is -4/3, I think.
A slope formula we were tought is y=mx + b where m always stands for slope. In this case, I transformed the formula Ax+By=C into By= -Ax+C. Since you need to get rid of the numerical coefficient of y, transpose B by dividing both sides by it.
From 3y= -4x+2, it will now look like y=(-4x+2)/3 or y=(-4x)/3 + 2/3 in simplest form. Since the slope is the numerical coefficient of x, -4/3 will then be the slope.
Reply:The easiest way to remember what to do is just to remember that the slope is the y-intercept
Reply:4x + 3y = 2
y = -4/3 x + 2/3
the equation is y = mx + b; where m is the slope..
therefore, -4/3 is your slope...
Hepatitis C Ttreatments?
My doctor wants me to do the standard combo treatments for Hep C But I'm somewhat apprehensive!, The side effects read like a rat poison label, i.e. Could cause cancer, diabetes (Which i'm border line now), Heart problems, anemia, mental problems, Suicide, Screw up your DNA, etc..., It sounds like the cure is worse than the disease!, And to top it off theirs only a 40 to 50% it will work!,( I'm geno type 1/ high viral load), This has been the ONLY treatment option for 10 years!, It seems they should of come up with a safer option by now?, Makes me wonder if the makers (Roche) have a Monopoly on it?, I'd like to hear from people who have done the treatments and their experiences, thoughts and advise?
Hepatitis C Ttreatments?
If you never try it, it will never work. You are really looking at the glass half empty. I did it 7 years ago, and cleared the virus. I have my energy back, and don't have to worry about cirrhosis or liver cancer. The pegylated interferon wasn't available 7 years ago; the side effects from the non-peg interferon were worse. I run a hep c support group, and have seen many people over the years have a sustained response (clear the virus). Overall, the success rate for genotype 1 is 50-57%. Pegasys (made by Roche)has a slightly higher response, and the people seem to have fewer side effects than on PegIntron (made by Schering-Plough). That's just a personal observation from the people in our support group(300+ members).
One thing I suggest: you have to have a good attitude before going into the chemo therapy like treatment. You might want to talk to more people who have done it and see what they did to improve their chances of staying on the medication long enough for it to work. I feel the mental preparation is at least half the battle. Our support group works hard to educate our members about the disease, the treatment, the side effects, %26amp; what they can do to deal with side effects. When you go into this battle knowing what you're up against, you are more likely to be able to deal with it. When you are able to deal with it, you are able to adhere to the treatment. Better adherance means you give the meds a chance to do it's job; clear the virus. Our support group also has a clinic that helps people without insurance get treatment. Both pharmaceutical companies have a patient assistance program and all but one person from our clinic have been given the medication for FREE (That's 51 out of 52 people who got their meds for free at a cost of $30,000 per person). So you see, while the medication is costly to those who are insured, they also have helped many people who would have never had a chance to get it. No, I don't work for the pharmaceutical company! But I am grateful for being a responder, and I'm also grateful for all our support group members who were given a chance to live a normal life, HCV free. Best wishes to you, whatever you decide to do.
Reply:You're not kidding, but I guess it's up to us to make some noise. It's the squeaky wheel that gets the grease! Report It
Reply:Not everyone is susceptible to the possible side effects. I know a number of people who have taken the Interferon injections and they believe they were infected for a very long period of time and their Hep C is undetectable today. The most common side effects they faced were depression and irritability. Two of the people I know are diabetics, not borderline and they took the treatments for 6 months and when they were finished their Hep C was undetectable and still is. My uncle has Hep C and same goes for him. He was a long time drug abuser and he feels that he was infected with Hep C for a very long period of time before he sought treatment and he is and has been freed from it which has been undetectable for quite a long time now.
I would seek out individuals who actually took the treatments and see what they say.
I hope all turns out well for you and as I have said I only know that the people I know have made it through and are better for it today. Best Wishes!
peony
Hepatitis C Ttreatments?
If you never try it, it will never work. You are really looking at the glass half empty. I did it 7 years ago, and cleared the virus. I have my energy back, and don't have to worry about cirrhosis or liver cancer. The pegylated interferon wasn't available 7 years ago; the side effects from the non-peg interferon were worse. I run a hep c support group, and have seen many people over the years have a sustained response (clear the virus). Overall, the success rate for genotype 1 is 50-57%. Pegasys (made by Roche)has a slightly higher response, and the people seem to have fewer side effects than on PegIntron (made by Schering-Plough). That's just a personal observation from the people in our support group(300+ members).
One thing I suggest: you have to have a good attitude before going into the chemo therapy like treatment. You might want to talk to more people who have done it and see what they did to improve their chances of staying on the medication long enough for it to work. I feel the mental preparation is at least half the battle. Our support group works hard to educate our members about the disease, the treatment, the side effects, %26amp; what they can do to deal with side effects. When you go into this battle knowing what you're up against, you are more likely to be able to deal with it. When you are able to deal with it, you are able to adhere to the treatment. Better adherance means you give the meds a chance to do it's job; clear the virus. Our support group also has a clinic that helps people without insurance get treatment. Both pharmaceutical companies have a patient assistance program and all but one person from our clinic have been given the medication for FREE (That's 51 out of 52 people who got their meds for free at a cost of $30,000 per person). So you see, while the medication is costly to those who are insured, they also have helped many people who would have never had a chance to get it. No, I don't work for the pharmaceutical company! But I am grateful for being a responder, and I'm also grateful for all our support group members who were given a chance to live a normal life, HCV free. Best wishes to you, whatever you decide to do.
Reply:You're not kidding, but I guess it's up to us to make some noise. It's the squeaky wheel that gets the grease! Report It
Reply:Not everyone is susceptible to the possible side effects. I know a number of people who have taken the Interferon injections and they believe they were infected for a very long period of time and their Hep C is undetectable today. The most common side effects they faced were depression and irritability. Two of the people I know are diabetics, not borderline and they took the treatments for 6 months and when they were finished their Hep C was undetectable and still is. My uncle has Hep C and same goes for him. He was a long time drug abuser and he feels that he was infected with Hep C for a very long period of time before he sought treatment and he is and has been freed from it which has been undetectable for quite a long time now.
I would seek out individuals who actually took the treatments and see what they say.
I hope all turns out well for you and as I have said I only know that the people I know have made it through and are better for it today. Best Wishes!
peony
Anybody knows the answers to the C.D.L general standards test?.?
Meaning the main written test. I'm an older person please help. Thanks.
Anybody knows the answers to the C.D.L general standards test?.?
MAX--
In California there are a total of 8 General Knowledge CDL tests, and the are ALL based on the driver's handbook issued by DMV.
The handbook doesn't cover EVERYTHING in the vehicle code, but the test is drawn from the handbook, and there aren't any questions asked from other sources.
HINT
Study the handbook, and study it well, but don't CRAM. Just study, and become familiar with the language and the concepts outlined in the handbook. Give particular attention to weights, lengths and limitations.
When you take the test, if you don't know the answer, look for the answer MOST wrong. This eliminates one, so now there are only three. If you still cannot see the correct answer clearly, eliminate the NEXT most wrong. Now ther are only two. If you still cannot make up your mind, even if you GUESS, you have a 50/50 chance of being right (or wrong)
Reply:why don't you read the hand book???
they use more than one test form so no one cheats and every state has different rules
Anybody knows the answers to the C.D.L general standards test?.?
MAX--
In California there are a total of 8 General Knowledge CDL tests, and the are ALL based on the driver's handbook issued by DMV.
The handbook doesn't cover EVERYTHING in the vehicle code, but the test is drawn from the handbook, and there aren't any questions asked from other sources.
HINT
Study the handbook, and study it well, but don't CRAM. Just study, and become familiar with the language and the concepts outlined in the handbook. Give particular attention to weights, lengths and limitations.
When you take the test, if you don't know the answer, look for the answer MOST wrong. This eliminates one, so now there are only three. If you still cannot see the correct answer clearly, eliminate the NEXT most wrong. Now ther are only two. If you still cannot make up your mind, even if you GUESS, you have a 50/50 chance of being right (or wrong)
Reply:why don't you read the hand book???
they use more than one test form so no one cheats and every state has different rules
Can someone help remind me how to put an equation in standard form?
I Know that the formula for standard form is Ax+By=C but how do I change the following equation for slope-intercept form back to standard form.
the equation is:
y=3/2x +4
Thanks for the help!!!
Can someone help remind me how to put an equation in standard form?
y = 3/2 x + 4
-3/2x + y = 4
(multiply by -2)
3x - 2y = -8
Reply:y=3/2x +4
-3/2x + y = 4 subtract x from the right and move it to the left
-3x +2y = 8 multiply the equation by two because A, B, %26amp; C have to be whole numbers
Reply:just transpose the ff
3/2x -y +4 = 0
multiply all by 2
3x -2y + 8 = 0
that's it
the equation is:
y=3/2x +4
Thanks for the help!!!
Can someone help remind me how to put an equation in standard form?
y = 3/2 x + 4
-3/2x + y = 4
(multiply by -2)
3x - 2y = -8
Reply:y=3/2x +4
-3/2x + y = 4 subtract x from the right and move it to the left
-3x +2y = 8 multiply the equation by two because A, B, %26amp; C have to be whole numbers
Reply:just transpose the ff
3/2x -y +4 = 0
multiply all by 2
3x -2y + 8 = 0
that's it
How do I convert slope intercept form to standard from?
I know slope intercept form is y=mx+b and standard form is Ax+By=C but how do i convert them back and forth, do i sjut sswitch the figures around?
How do I convert slope intercept form to standard from?
slope intercept form is
y=mx+b
transposing you get y-mx-b=0
multiplying by (-1)
mx+y+b=0
if the slope intercept form is y=(a/b)x+k
by=ax+bk
transposing
by-ax-bk=0
multiplying by (-1( and writing bk as c
ax+by+c=0 which is the standard form
Reply:A simple switching of the figures should work, but I'd check your textbook first.
Reply:y=mx+b
=%26gt; mx-y+b=0
=%26gt; mx-y = -b
this is in the standard form A=m, B=-1, C=-b
Reply:If you have a formula
y = mx + c
and you want to get it into Ax + By + C = 0
Then you must do some rearranging.
subtract y from both sides
0 = mx - y + c
Reply:yes
How do I convert slope intercept form to standard from?
slope intercept form is
y=mx+b
transposing you get y-mx-b=0
multiplying by (-1)
mx+y+b=0
if the slope intercept form is y=(a/b)x+k
by=ax+bk
transposing
by-ax-bk=0
multiplying by (-1( and writing bk as c
ax+by+c=0 which is the standard form
Reply:A simple switching of the figures should work, but I'd check your textbook first.
Reply:y=mx+b
=%26gt; mx-y+b=0
=%26gt; mx-y = -b
this is in the standard form A=m, B=-1, C=-b
Reply:If you have a formula
y = mx + c
and you want to get it into Ax + By + C = 0
Then you must do some rearranging.
subtract y from both sides
0 = mx - y + c
Reply:yes
Standard free-energy change?
Calculate the standard free-energy change at 25°C for the following reaction. Use standard electrode potentials.
4 Al(s) + 3 O2(g) + 12 H^+(aq) 4 Al^3+(aq) + 6 H2O(l)
long stem roses
4 Al(s) + 3 O2(g) + 12 H^+(aq) 4 Al^3+(aq) + 6 H2O(l)
long stem roses
Standard Electrode Potentials?
Calculate the standard free-energy change at 25°C for the following reaction. Use standard electrode potentials.
4 Al(s) + 3 O2(g) + 12 H+(aq) --%26gt; 4 Al3+(aq) + 6 H2O(l)
_________ J
Standard Electrode Potentials?
The half reactions and their standard electrode potentials are
(I) :
Al³⁺ + 3 e⁺ ⇌ Al(s)
E°(I) = -1.66 V
(II) :
O₂(g) + 4 H⁺ + 4 e⁻ ⇌ 2 H₂O(l)
E°(II) = +1.23 V
Overall reaction is three times reaction (II) forward plus 4 times reaction (I) reverse:
3·(II)-4·(I) : 4 Al(s) + 3 O₂(g) + 12 H⁺ + 4 e⁻ ⇌ 4Al³⁺ + 6 H₂O(l)
Hence:
ΔE° = 3·E°(II) - 4·E°(I)
= 3·(+1.23VI) - 4·(-1.66V)
= +10.33 V
Gibbs energy of reaction and potential difference are related as:
ΔG° = - z·F·ΔE°
where
z number of electrons exchanged
F Faraday constant
So for this reaction:
ΔG° = - 12 · 96485C/mol · +10.33V = 11960 J/mol
4 Al(s) + 3 O2(g) + 12 H+(aq) --%26gt; 4 Al3+(aq) + 6 H2O(l)
_________ J
Standard Electrode Potentials?
The half reactions and their standard electrode potentials are
(I) :
Al³⁺ + 3 e⁺ ⇌ Al(s)
E°(I) = -1.66 V
(II) :
O₂(g) + 4 H⁺ + 4 e⁻ ⇌ 2 H₂O(l)
E°(II) = +1.23 V
Overall reaction is three times reaction (II) forward plus 4 times reaction (I) reverse:
3·(II)-4·(I) : 4 Al(s) + 3 O₂(g) + 12 H⁺ + 4 e⁻ ⇌ 4Al³⁺ + 6 H₂O(l)
Hence:
ΔE° = 3·E°(II) - 4·E°(I)
= 3·(+1.23VI) - 4·(-1.66V)
= +10.33 V
Gibbs energy of reaction and potential difference are related as:
ΔG° = - z·F·ΔE°
where
z number of electrons exchanged
F Faraday constant
So for this reaction:
ΔG° = - 12 · 96485C/mol · +10.33V = 11960 J/mol
I have to change quadrants into standard form how do i do it?
my first problem is;
(0,0) (1,4)
standard form is ;
Ax+By=C
how do i do it?
I have to change quadrants into standard form how do i do it?
first find the slope. use m=(y2-y1)/(x2-x1). this gives us 4-0/1-0 which = 4/1 or a slope of 4.
now put it in point- slope form. y-y1=m(x-x1) giving y-4=4(x-1).
next distribute the 4 giving y-4=4x-4. now subtract y from both sides giving -4=4x-y-4.
finally, add 4 to each side giving 4x-y=0.
A=4, B=-1 and C=0
(0,0) (1,4)
standard form is ;
Ax+By=C
how do i do it?
I have to change quadrants into standard form how do i do it?
first find the slope. use m=(y2-y1)/(x2-x1). this gives us 4-0/1-0 which = 4/1 or a slope of 4.
now put it in point- slope form. y-y1=m(x-x1) giving y-4=4(x-1).
next distribute the 4 giving y-4=4x-4. now subtract y from both sides giving -4=4x-y-4.
finally, add 4 to each side giving 4x-y=0.
A=4, B=-1 and C=0
What is y=-11x-4 in standard form?
The formula for standard for is Ax+By=C
What is y=-11x-4 in standard form?
11x + y = -4.
what's the problem?
A and B are symbols for numbers, and if you move a term from a part to another of the = , you have to change the sign (- or +)
sorry for the english
Reply:For standard form the number in front of the x is A, so in this case 11. The number in front of the y is B, so in this case 1. You have to add the 11x to both sides.
11x+y=-4
Reply:44
Reply:y=(-11)x-4
y+4=(-11)x-4+4
y+4=(-11)x
y-y+4=(-11)x-y
4=(-11)x-y
-(4=(-11)x-y)
(-4)=11x+y
What is y=-11x-4 in standard form?
11x + y = -4.
what's the problem?
A and B are symbols for numbers, and if you move a term from a part to another of the = , you have to change the sign (- or +)
sorry for the english
Reply:For standard form the number in front of the x is A, so in this case 11. The number in front of the y is B, so in this case 1. You have to add the 11x to both sides.
11x+y=-4
Reply:44
Reply:y=(-11)x-4
y+4=(-11)x-4+4
y+4=(-11)x
y-y+4=(-11)x-y
4=(-11)x-y
-(4=(-11)x-y)
(-4)=11x+y
C coding...wats wrong with this Code... regarding inline function?
C coding...
I heard that C99 standard support inline functions in C...
But the following code is not getting compiled...
wats wrong with this...
plz someone help
#include %26lt;stdio.h%26gt;
inline int func(int i);
int main()
{
int i=5;
printf("\nBefore inline func...");
func(i);
printf("\nAfter inline func...\n\n");
return 0;
}
inline int func(int i)
{
printf("\nIn inline function...");
return i;
}
C coding...wats wrong with this Code... regarding inline function?
what compiler are you using, and what is the compiler error message?
if you're using a microsoft compiler you need to use the new style: __inline
also, make func() return void instead of int, since you aren't using the return value.
gifts
I heard that C99 standard support inline functions in C...
But the following code is not getting compiled...
wats wrong with this...
plz someone help
#include %26lt;stdio.h%26gt;
inline int func(int i);
int main()
{
int i=5;
printf("\nBefore inline func...");
func(i);
printf("\nAfter inline func...\n\n");
return 0;
}
inline int func(int i)
{
printf("\nIn inline function...");
return i;
}
C coding...wats wrong with this Code... regarding inline function?
what compiler are you using, and what is the compiler error message?
if you're using a microsoft compiler you need to use the new style: __inline
also, make func() return void instead of int, since you aren't using the return value.
gifts
Write this equation in standard form using integers?
y = -1/3x + 2
remember standard form is Ax + By + C, so x and y must be on the same side.
Write this equation in standard form using integers?
y = - 1/3x + 2
3y = - x + 6
x + 3y = 6
Reply:multiply by 3 to clear the fraction
3y=-x+6
x+3y-6=0
remember standard form is Ax + By + C, so x and y must be on the same side.
Write this equation in standard form using integers?
y = - 1/3x + 2
3y = - x + 6
x + 3y = 6
Reply:multiply by 3 to clear the fraction
3y=-x+6
x+3y-6=0
Let Z be a standard normal random variable?
Let Z be a standard normal random variable
P(-c %26lt; Z %26lt; -0.68) = 0.2312
Carry your intermediate computations to at least four decimal places. Round your answer to at least two decimal places
Let Z be a standard normal random variable?
-2.12
The area from 0 to -2.12 is 0.4830
The area from 0 to -0.68 is 0.2517
The difference is 0.2313
innia
P(-c %26lt; Z %26lt; -0.68) = 0.2312
Carry your intermediate computations to at least four decimal places. Round your answer to at least two decimal places
Let Z be a standard normal random variable?
-2.12
The area from 0 to -2.12 is 0.4830
The area from 0 to -0.68 is 0.2517
The difference is 0.2313
innia
Microsoft Excel: Calculating Standard Deviations?
In column (A) of an Excel spreadsheet, I have calculated a 150-day simple moving average (sma), updated daily, for each day over a period of 3000 days. In column (B) I want to calculate the corresponding values for 1 standard deviation from the 150-day sma. In Column (C) I want to calculate 2 standard deviations from the 150 sma and in Column D, I want to calculate 3 standard deviations from the 150 sma. What would be the formulas for Columns (B), (C) and (D)? Thank you.
Microsoft Excel: Calculating Standard Deviations?
You probably want to put everything in its own column:
So column A is the average, B is the stdev, column C is your A - B, column D is A + B, column E is A - 2B, etc. If you have the data on some other sheet, you might use conditional formatting to highlight the values that fall outside the 1 SD, 2SD ranges.
Reply:If col A contains the averages and col B has the standard deviations [stdev(range)], then cells C1 through H1 would be:
=A1-B1
=A1+B1
=A1-2*B1
=A1+2*B1
=A1-3*B1
=A1+3*B1
And similarly for cells C2 through H2, C3 through H3, etc.
Hope this helps.
Reply:http://www.convert-me.com/en/
Reply:the excel command for standard deviation is stdev(range) where the range is the list of numbers for which you want to calculate the std
you can easily mulitply 2* that value, 3* that value, or whatever
care should be taken to make sure you are getting the standard deviation you want
the standard deviation of the group of data that is each day's result, is different than the standard deviation of the moving average
Microsoft Excel: Calculating Standard Deviations?
You probably want to put everything in its own column:
So column A is the average, B is the stdev, column C is your A - B, column D is A + B, column E is A - 2B, etc. If you have the data on some other sheet, you might use conditional formatting to highlight the values that fall outside the 1 SD, 2SD ranges.
Reply:If col A contains the averages and col B has the standard deviations [stdev(range)], then cells C1 through H1 would be:
=A1-B1
=A1+B1
=A1-2*B1
=A1+2*B1
=A1-3*B1
=A1+3*B1
And similarly for cells C2 through H2, C3 through H3, etc.
Hope this helps.
Reply:http://www.convert-me.com/en/
Reply:the excel command for standard deviation is stdev(range) where the range is the list of numbers for which you want to calculate the std
you can easily mulitply 2* that value, 3* that value, or whatever
care should be taken to make sure you are getting the standard deviation you want
the standard deviation of the group of data that is each day's result, is different than the standard deviation of the moving average
Help me understand standard form?
i know that standard form is Ax + By + C = 0, but i'm having trouble understanding what values you would plug into the equation.
lets say that the equation is y=9x+5
Help me understand standard form?
are you sure this is standard form cuz when I learnt it it wasnt nothin like this..
Standard form is a way of writing down very large or very small numbers easily. 10³ = 1000, so 4 × 10³ = 4000 . So 4000 can be written as 4 × 10³ . This idea can be used to write even larger numbers down easily in standard form.
The rules when writing a number in standard form is that first you write down a number between 1 and 10, then you write × 10(to the power of a number).
Example
Write 81 900 000 000 000 in standard form:
81 900 000 000 000 = 8.19 × 1013
It’s 1013 because the decimal point has been moved 13 places to the left to get the number to be 8.19
Example
Write 0.000 001 2 in standard form:
0.000 001 2 = 1.2 × 10-6
It’s 10-6 because the decimal point has been moved 6 places to the right to get the number to be 1.2
On a calculator, you usually enter a number in standard form as follows:
Type in the first number (the one between 1 and 10). Press EXP . Type in the power to which the 10 is risen.
lets say that the equation is y=9x+5
Help me understand standard form?
are you sure this is standard form cuz when I learnt it it wasnt nothin like this..
Standard form is a way of writing down very large or very small numbers easily. 10³ = 1000, so 4 × 10³ = 4000 . So 4000 can be written as 4 × 10³ . This idea can be used to write even larger numbers down easily in standard form.
The rules when writing a number in standard form is that first you write down a number between 1 and 10, then you write × 10(to the power of a number).
Example
Write 81 900 000 000 000 in standard form:
81 900 000 000 000 = 8.19 × 1013
It’s 1013 because the decimal point has been moved 13 places to the left to get the number to be 8.19
Example
Write 0.000 001 2 in standard form:
0.000 001 2 = 1.2 × 10-6
It’s 10-6 because the decimal point has been moved 6 places to the right to get the number to be 1.2
On a calculator, you usually enter a number in standard form as follows:
Type in the first number (the one between 1 and 10). Press EXP . Type in the power to which the 10 is risen.
Equation's in standard form?
write each equation in standard form where a b c are integers whose greatest common factor is 1.
y = 7x+ 15?
what is standars form and how do i write something in it?
Equation's in standard form?
Standard form is y= mx + b, or using your a,b,c coefficients, ay = bx + c
By saying "whose greatest common factor is 1" is simply stating that there's no integer greater than 1 that can evenly divide each of a, b, and c
For example, this is not in standard form because each coefficient is divisible by 3:
6y = 9x + 12
However if you divide it by 3 to get the following:
2y = 3x + 4
This is now in standard form. Even though 2 divides 2 and 4, it doesn't divide 3, and you can't simplify this equation any further.
HTH! :-)
PS -- yes, y = 7x+ 15 is already in standard form
Reply:Did your instructor give you an example of standard form?
y = 7x+ 15 is one standard form (y = mx + b)
Another is ax + by = c, or
-7x +y = 15.
Yet a third standard form is
ax + by + c = 0, or
-7x + y - 15 = 0
One more:
y = a + bx + cx^2 + .....
y = 15 + 7x
Reply:Please refine your question. I'm not sure what you want.
Do you want and equivalent equation where
ay = bx + c where a,b,c are relatively prime?
y = 7x+ 15?
what is standars form and how do i write something in it?
Equation's in standard form?
Standard form is y= mx + b, or using your a,b,c coefficients, ay = bx + c
By saying "whose greatest common factor is 1" is simply stating that there's no integer greater than 1 that can evenly divide each of a, b, and c
For example, this is not in standard form because each coefficient is divisible by 3:
6y = 9x + 12
However if you divide it by 3 to get the following:
2y = 3x + 4
This is now in standard form. Even though 2 divides 2 and 4, it doesn't divide 3, and you can't simplify this equation any further.
HTH! :-)
PS -- yes, y = 7x+ 15 is already in standard form
Reply:Did your instructor give you an example of standard form?
y = 7x+ 15 is one standard form (y = mx + b)
Another is ax + by = c, or
-7x +y = 15.
Yet a third standard form is
ax + by + c = 0, or
-7x + y - 15 = 0
One more:
y = a + bx + cx^2 + .....
y = 15 + 7x
Reply:Please refine your question. I'm not sure what you want.
Do you want and equivalent equation where
ay = bx + c where a,b,c are relatively prime?
Change this to standard form?
i know that standard from is Ax + By + C = 0
I just don't know how what values go where...
Change this to standard form?
Perhaps
Ax + By = C
Reply:Standard form is Ax + By = C
okay.. umm well for example if a point was (3,5) then you would plug it in as
3x + 5y = C
gerbera
I just don't know how what values go where...
Change this to standard form?
Perhaps
Ax + By = C
Reply:Standard form is Ax + By = C
okay.. umm well for example if a point was (3,5) then you would plug it in as
3x + 5y = C
gerbera
Help me write equations in standard form?
Write each equation in standard form.
My teacher said standard form is ax + by = c
How do you put -4/9 + 2/9y = x in that form?
And most confusing, how do you put y= -1/2 in that form?!
Help me write equations in standard form?
x - 2/9y = -4/9; where a = 1, b = -2/9, and c = -4/9
y = -1/2 is already in standard form since a = 0, b = 1, and c = -1/2.
0x + 1y = -1/2 is the same thing as y = -1/2.
My teacher said standard form is ax + by = c
How do you put -4/9 + 2/9y = x in that form?
And most confusing, how do you put y= -1/2 in that form?!
Help me write equations in standard form?
x - 2/9y = -4/9; where a = 1, b = -2/9, and c = -4/9
y = -1/2 is already in standard form since a = 0, b = 1, and c = -1/2.
0x + 1y = -1/2 is the same thing as y = -1/2.
Statistics-mean-standard deviation?
A huge vat is full of marbles all mixed together, with a number written on it. 20% of the marbles have a "0", 30% have a "1", 10% have a "15", 10% have a "30", 10% have a "80" , and the rest have a"100". Let Y be a number written on a randomly-selected marble (round all answers to four decimal places)
[a]The mean of the random variable Y is:?
[b]The Standard Dev. of Y is:?
[c]Take 20 marbles. What is the probability that the number of "ones" is at most 5:?
[d]Take 100 Marbles. What is the prob. that the number of "ones" is at most 25:?
[e]The prob of the average of numbers on n=25 is less than 35 is:?
For a sample of n=81 it would be:?
For a sample of n=400 it would be:?
For a sample of n=1600 it would be:?
For a sample of n=6400 it would be:?
Statistics-mean-standard deviation?
a) mean is just a weighted average:
m = .20(0) + .30(1) + .1(15) + .1(30) + .1(80) +.2(100) = 32.8
b) standard deviation:
SD = sqrt[.20((-32.8)^2) + .30((-31.8)^2) + .10((-17.8)^2) + .10((-2.8)^2) + .10(47.2^2) +.20(67.2^2)] = 39.0629
c) Since it's a "huge vat", we'll assume that taking out 20 marbles doesn't affect the proportions of the different kinds of marbles in the vat. The probability of exactly
zero "ones" = (1-.3)^20 = 0.000797923
one "one" = 20(.3*.7^19) = 0.006839337
two "ones" = (20*19)(.3^2*.7^18)/2 = 0.027845873
three "ones" = (20*19*18)(.3^3*.7^17)/6 = 0.071603672
four "ones" = ... = 0.130420974
five "ones" = ... = 0.178863051
Adding these up gives 0.416370829 as the probability of getting at most five "ones".
d) Exact same logic as before gives probability of 0.163130104 for getting at most twenty-five "ones".
e) sorry, no time to work on this last one -- you'll have to find someone else.
Reply:....0 | 0.20 |.. 0.0 | 215.168
....1 | 0.30 |.. 0.3 | 303.372
..15 | 0.10 |.. 1.5 |.. 31.684
..30 | 0.10 |.. 3.0 |.... 0.784
..80 | 0.10 |.. 8.0 | 222.784
100 | 0.20 | 20.0 | 903.168
[a] μ = 32.8
[b] σ ≈ 40.95070
[c] 1 - 0.7^15 ≈ 0.9952524
[d] 1 - 0.7^75 ≈ 1.0
[e] Z = 5(35 - 32.8) / 40.95070 = 0.2686157
P(m %26lt; 35) = 0.605889
etc.
Reply:let Y=number written
y ---- p(y)
0-----0.20
1-----0.30
15----0.10
30----0.10
80----0.10
100--0.20
mean= E(y) = sum y(i).p(y(i) for each i
0(0.20)+1(0.30)+15(0.10)+30(0.10)+80(0...
b) find variance of y
[y-E(y)]^2
[0-32.8]^2=1075.84
[1-32.8]^2=1011.24
..
..
[100-32.8]^2=4515.84
add all (y-E(y))^2 and take its square root.
It's your standard deviation.
c)prob (y=1)=0.30
Use a Binomial distribution with n=20 p=0.3
x=0,1,2,3,4,5 and sum these values
Use the source if you don't have a Binomial table.=0.4164
d)n=100 p=0.3 x=0 through 25.
=0.1631
e) The question is not clear. What is your definition of n? I have defined n as my number of marbles. The probability of a marble showing less than 35 is 0.70 from the table.
average of numbers is 32.8 .
p(av %26lt; 35)=p(z %26lt; (35-32.8)/sd/sqrt(25)) -- (1)assuming a normal distribution)
sd can be computed from the table.
for a sample of n=81
replace 25 by 81 in (1)
and so on. Use the normal table to evaluate these probabilities.
[a]The mean of the random variable Y is:?
[b]The Standard Dev. of Y is:?
[c]Take 20 marbles. What is the probability that the number of "ones" is at most 5:?
[d]Take 100 Marbles. What is the prob. that the number of "ones" is at most 25:?
[e]The prob of the average of numbers on n=25 is less than 35 is:?
For a sample of n=81 it would be:?
For a sample of n=400 it would be:?
For a sample of n=1600 it would be:?
For a sample of n=6400 it would be:?
Statistics-mean-standard deviation?
a) mean is just a weighted average:
m = .20(0) + .30(1) + .1(15) + .1(30) + .1(80) +.2(100) = 32.8
b) standard deviation:
SD = sqrt[.20((-32.8)^2) + .30((-31.8)^2) + .10((-17.8)^2) + .10((-2.8)^2) + .10(47.2^2) +.20(67.2^2)] = 39.0629
c) Since it's a "huge vat", we'll assume that taking out 20 marbles doesn't affect the proportions of the different kinds of marbles in the vat. The probability of exactly
zero "ones" = (1-.3)^20 = 0.000797923
one "one" = 20(.3*.7^19) = 0.006839337
two "ones" = (20*19)(.3^2*.7^18)/2 = 0.027845873
three "ones" = (20*19*18)(.3^3*.7^17)/6 = 0.071603672
four "ones" = ... = 0.130420974
five "ones" = ... = 0.178863051
Adding these up gives 0.416370829 as the probability of getting at most five "ones".
d) Exact same logic as before gives probability of 0.163130104 for getting at most twenty-five "ones".
e) sorry, no time to work on this last one -- you'll have to find someone else.
Reply:....0 | 0.20 |.. 0.0 | 215.168
....1 | 0.30 |.. 0.3 | 303.372
..15 | 0.10 |.. 1.5 |.. 31.684
..30 | 0.10 |.. 3.0 |.... 0.784
..80 | 0.10 |.. 8.0 | 222.784
100 | 0.20 | 20.0 | 903.168
[a] μ = 32.8
[b] σ ≈ 40.95070
[c] 1 - 0.7^15 ≈ 0.9952524
[d] 1 - 0.7^75 ≈ 1.0
[e] Z = 5(35 - 32.8) / 40.95070 = 0.2686157
P(m %26lt; 35) = 0.605889
etc.
Reply:let Y=number written
y ---- p(y)
0-----0.20
1-----0.30
15----0.10
30----0.10
80----0.10
100--0.20
mean= E(y) = sum y(i).p(y(i) for each i
0(0.20)+1(0.30)+15(0.10)+30(0.10)+80(0...
b) find variance of y
[y-E(y)]^2
[0-32.8]^2=1075.84
[1-32.8]^2=1011.24
..
..
[100-32.8]^2=4515.84
add all (y-E(y))^2 and take its square root.
It's your standard deviation.
c)prob (y=1)=0.30
Use a Binomial distribution with n=20 p=0.3
x=0,1,2,3,4,5 and sum these values
Use the source if you don't have a Binomial table.=0.4164
d)n=100 p=0.3 x=0 through 25.
=0.1631
e) The question is not clear. What is your definition of n? I have defined n as my number of marbles. The probability of a marble showing less than 35 is 0.70 from the table.
average of numbers is 32.8 .
p(av %26lt; 35)=p(z %26lt; (35-32.8)/sd/sqrt(25)) -- (1)assuming a normal distribution)
sd can be computed from the table.
for a sample of n=81
replace 25 by 81 in (1)
and so on. Use the normal table to evaluate these probabilities.
ALG 1 Standard form?
Can someone help me? Write each equation in standard form.
formula : Ax+By=C
y + 2 = 4(x+2)
y+1= -7(x+1)
y-3= -5(x+12)
y-5 = 3/2 (x+4)
y-1/4 = -3( x + 1/4 )
y-2/3 = -2( x-1/4 )
PLEASE AND THANK YOU?
ALG 1 Standard form?
you're lucky i enjoy these, otherwise i'd tell you to do your own homework.....
y+2 = 4(x+2) -----%26gt; y= 4x+6
y+1= -7(x+1) -----%26gt; y= -7x-8
y-3= -5(x+12) ----%26gt; y= -5x-57
y-5 = 3/2 (x+4) ---%26gt; y= 3/2x+11
i hate fractions. you can do those on your own.
Reply:You should just do those yourself because you will have to show your work. You will learn better this way. Those are not too difficult. Just distribute when you see a number times a sum. and isolate y.
formula : Ax+By=C
y + 2 = 4(x+2)
y+1= -7(x+1)
y-3= -5(x+12)
y-5 = 3/2 (x+4)
y-1/4 = -3( x + 1/4 )
y-2/3 = -2( x-1/4 )
PLEASE AND THANK YOU?
ALG 1 Standard form?
you're lucky i enjoy these, otherwise i'd tell you to do your own homework.....
y+2 = 4(x+2) -----%26gt; y= 4x+6
y+1= -7(x+1) -----%26gt; y= -7x-8
y-3= -5(x+12) ----%26gt; y= -5x-57
y-5 = 3/2 (x+4) ---%26gt; y= 3/2x+11
i hate fractions. you can do those on your own.
Reply:You should just do those yourself because you will have to show your work. You will learn better this way. Those are not too difficult. Just distribute when you see a number times a sum. and isolate y.
Standard form?
standard form is ax +by = c
so how do i find the dstandard form of the equation of the line with slope of -6 and passing through the points (9,7) ??
Standard form?
Slope is basically the "x", and it already says the slope is -6.
use the formula, y-y1=m(x-x1).
You know that"x(1)"=9 "y(1)"=7, and "y(1)"=7, so to sub it in:
y-7=-6(x-9).
y-7=-6x+54
y=-6x+61 %26lt;---- That is in point slope form.
To set it in standard form, add 6x to the left side to get:
****6x+y=61**** %26lt;----- That is in standard form
Hope this helps
Reply:slope = rise/run = delta y/delta x
so we know slope and one point...need another point (x,y) to get delta x and delta y
-6 = (7-y)/(9-x)
-54 + 6x = 7 - y
6x + y = 61
rosemary
so how do i find the dstandard form of the equation of the line with slope of -6 and passing through the points (9,7) ??
Standard form?
Slope is basically the "x", and it already says the slope is -6.
use the formula, y-y1=m(x-x1).
You know that"x(1)"=9 "y(1)"=7, and "y(1)"=7, so to sub it in:
y-7=-6(x-9).
y-7=-6x+54
y=-6x+61 %26lt;---- That is in point slope form.
To set it in standard form, add 6x to the left side to get:
****6x+y=61**** %26lt;----- That is in standard form
Hope this helps
Reply:slope = rise/run = delta y/delta x
so we know slope and one point...need another point (x,y) to get delta x and delta y
-6 = (7-y)/(9-x)
-54 + 6x = 7 - y
6x + y = 61
rosemary
Standard form of of the equation of the line:slope=2/3 intercepts are (2,5) (5,7) how u get TO the answer?thx
ok the answer is -2x+3y=11 but i have no idea where they come from. standard form is Ax+By=C
Standard form of of the equation of the line:slope=2/3 intercepts are (2,5) (5,7) how u get TO the answer?thx
y=mx+b
You got everything here man check it out
plug in your numbers
5=2/3(2) +b
7= 2/3(7) + b
or you could do this m= (y-y1)/ (x-x1)
Standard form of of the equation of the line:slope=2/3 intercepts are (2,5) (5,7) how u get TO the answer?thx
y=mx+b
You got everything here man check it out
plug in your numbers
5=2/3(2) +b
7= 2/3(7) + b
or you could do this m= (y-y1)/ (x-x1)
ALgebra!!!!!!!!! "Standard form"?
Write the equation in standard form with integer coefficients.
x-5=0
the standard formula is --%26gt;%26gt;%26gt;%26gt; Ax+By=C
ALgebra!!!!!!!!! "Standard form"?
x = 5
For the standard formula, you have to make sure the coefficient A is positive.
C is your constant, which makes sense since you have a 5 there.
Reply:1x = 5
Reply:0=5-x
add 5 to both sides geting X= 0-5 then add 0 to both sides so 0+X=5 and then subtrace X from both sides geting
0=5-X
standard notation is that =)
x-5=0
the standard formula is --%26gt;%26gt;%26gt;%26gt; Ax+By=C
ALgebra!!!!!!!!! "Standard form"?
x = 5
For the standard formula, you have to make sure the coefficient A is positive.
C is your constant, which makes sense since you have a 5 there.
Reply:1x = 5
Reply:0=5-x
add 5 to both sides geting X= 0-5 then add 0 to both sides so 0+X=5 and then subtrace X from both sides geting
0=5-X
standard notation is that =)
Standard form??
standard form is ax +by = c
so0o how do u write an equation in standard form for the line that contains each pair of points like:
1. (3,8), (6,4)
2. (-2, -1), (2,2)
Standard form??
slope = (y1-y2)/(x1-x2)
1) (8-4)/(3-6)=-4/3
2) (-1-2)/(-2-2)= 3/4
y=mx+b in slope intercept form
1) y= -4/3x + b
4= -4/3(6)+b
4=-8 + b
b=12
2) y=3/4x+b
2=3/4(2)+b
2=3/2+b
b=1/2
rearrange from s-i form to standard form
1) y=-4/3x+12
3y=-4x+36
3y+4x=36
2) y=3/4x+1/2
4y=3x+2
4y-3x=2
Reply:There are several ways of writing down the equation of a line depending on what information you are given. The slope / intercept form which has already been mentioned is only one way of looking at it. Your geometry text should give you at least one other method which is more directly revelant when you know two points through which the line passes, and it is a very useful one to commit to memory.
Call the two points which you are given (x1, y1) and (x2, y2).
Then the general form of the equation of the line passing through these two points is
(y - y1) / (x -x1) = (y2 -y1) / (x2 - x1)
So in this case , having the points (-2, -1) and ( 2, 2 ) you get
( y - (-1)) / ( x - (-2)) = ( 2 - (-1 )) / ( 2 - (-2))
which becomes : ( y + 1 ) / ( x + 2 ) = 3 / 4
(note that you have to be VERY careful with the minus signs in this, but it shouldn't be a problem if you write everything down carefully as above and don't try to take any short cuts !)
Then rearrange ( "cross multiply") to give
4( y + 1 ) = 3 ( x + 2 )
4y + 4 = 3x + 6
4y = 3x + 2
Finally, check that you haven't made any silly mistakes with the signs by putting into the equation the values for x which you have been given, and verifying that they produce the correct values for y.
Note also that it does not matter which point you call (x1, y1) and which (x2, y2) - as long as you are careful about the minus signs, you will get the same answer.
so0o how do u write an equation in standard form for the line that contains each pair of points like:
1. (3,8), (6,4)
2. (-2, -1), (2,2)
Standard form??
slope = (y1-y2)/(x1-x2)
1) (8-4)/(3-6)=-4/3
2) (-1-2)/(-2-2)= 3/4
y=mx+b in slope intercept form
1) y= -4/3x + b
4= -4/3(6)+b
4=-8 + b
b=12
2) y=3/4x+b
2=3/4(2)+b
2=3/2+b
b=1/2
rearrange from s-i form to standard form
1) y=-4/3x+12
3y=-4x+36
3y+4x=36
2) y=3/4x+1/2
4y=3x+2
4y-3x=2
Reply:There are several ways of writing down the equation of a line depending on what information you are given. The slope / intercept form which has already been mentioned is only one way of looking at it. Your geometry text should give you at least one other method which is more directly revelant when you know two points through which the line passes, and it is a very useful one to commit to memory.
Call the two points which you are given (x1, y1) and (x2, y2).
Then the general form of the equation of the line passing through these two points is
(y - y1) / (x -x1) = (y2 -y1) / (x2 - x1)
So in this case , having the points (-2, -1) and ( 2, 2 ) you get
( y - (-1)) / ( x - (-2)) = ( 2 - (-1 )) / ( 2 - (-2))
which becomes : ( y + 1 ) / ( x + 2 ) = 3 / 4
(note that you have to be VERY careful with the minus signs in this, but it shouldn't be a problem if you write everything down carefully as above and don't try to take any short cuts !)
Then rearrange ( "cross multiply") to give
4( y + 1 ) = 3 ( x + 2 )
4y + 4 = 3x + 6
4y = 3x + 2
Finally, check that you haven't made any silly mistakes with the signs by putting into the equation the values for x which you have been given, and verifying that they produce the correct values for y.
Note also that it does not matter which point you call (x1, y1) and which (x2, y2) - as long as you are careful about the minus signs, you will get the same answer.
Find standard deviation and percentage of sample within given means?
You count the number of beta rays from a 137Cs source. You do this 20 times during the same period of time and find the following number of counts: 1044, 1154, 1106, 1055, 1086, 1112, 1079, 1087, 1079, 1060, 1128, 1059, 1055, 1092, 1038, 1117, 1141, 1083, 1141, and 1128.
a) What is the average number of counts?
1092.2
b) What is the (sample) standard deviation of your sample?
______
c) What percentage of your sample of numbers should be within %26lt; N %26gt; +/-2 sq rt %26lt; N %26gt; ?
______%
FOUND PART a BUT DON'T KNOW HOW TO DO PART b AND c
THANK YOU!
Find standard deviation and percentage of sample within given means?
You're in the wrong category...this is a Mathematics question. The good news is that physicists have all the math to answer.
The standard deviation (SD) is a sort of average, like the mean. The difference is that this is the average of the square of the difference between each data point and the mean. This difference is d = x - m; where x is your data (1044, 1154, ... , 1128) and m is the mean m = 1092.2.
As the average of the square of the difference we find something called the variance, which is just Var = SD^2 = SUM(d^2)/N; where N is the number of data points. If the number of data points is just a sampling of all data points, then for reasons usually uncovered in advanced statistics, we use n = N - 1 to average out the d^2. n is called the degrees of freedom.
So there we have it, the standard deviation is SD = sqrt(SUM((x - m)^2)/(N - 1)); where N = 20 data points and m = 1092.2 counts. Find d = x - m for each data point x, square it and add all the d^2. Then divide that SUM by N - 1. That will give you the variance Var. Take sqrt(Var) = SD.
As to c., if you assume the probability distribution of the sample counts is Normal, then you should know that 95% of your counts will lie between +- 2SD on either side of the mean m. After you find SD, add 2SD to your mean m for the upper bound and substract 2SD from your mean for the lower bound. 95% of all your counts should lie between the upper and lower bounds, which are at the +- 2SD marks.
wallflower
a) What is the average number of counts?
1092.2
b) What is the (sample) standard deviation of your sample?
______
c) What percentage of your sample of numbers should be within %26lt; N %26gt; +/-2 sq rt %26lt; N %26gt; ?
______%
FOUND PART a BUT DON'T KNOW HOW TO DO PART b AND c
THANK YOU!
Find standard deviation and percentage of sample within given means?
You're in the wrong category...this is a Mathematics question. The good news is that physicists have all the math to answer.
The standard deviation (SD) is a sort of average, like the mean. The difference is that this is the average of the square of the difference between each data point and the mean. This difference is d = x - m; where x is your data (1044, 1154, ... , 1128) and m is the mean m = 1092.2.
As the average of the square of the difference we find something called the variance, which is just Var = SD^2 = SUM(d^2)/N; where N is the number of data points. If the number of data points is just a sampling of all data points, then for reasons usually uncovered in advanced statistics, we use n = N - 1 to average out the d^2. n is called the degrees of freedom.
So there we have it, the standard deviation is SD = sqrt(SUM((x - m)^2)/(N - 1)); where N = 20 data points and m = 1092.2 counts. Find d = x - m for each data point x, square it and add all the d^2. Then divide that SUM by N - 1. That will give you the variance Var. Take sqrt(Var) = SD.
As to c., if you assume the probability distribution of the sample counts is Normal, then you should know that 95% of your counts will lie between +- 2SD on either side of the mean m. After you find SD, add 2SD to your mean m for the upper bound and substract 2SD from your mean for the lower bound. 95% of all your counts should lie between the upper and lower bounds, which are at the +- 2SD marks.
wallflower
Standard form??
ok so i kno that standard form is ax + by = c
how woul di find the standard form of the equation of the line that passes through the oints (-5, 4) and (-8, -6)
Standard form??
Hi,
In a few syllables: Use the point-slope form of a linear equation, which is this:
y -y1 = m(x-x1) (Where m is the slope and (x1,y1) is either of the two points. Here's how to use it:
1) First we need the slope:
m = (y2-y1)/(x2-x1) (We can choose either point as (x1,y1)
m = (-6 -4)/(-8- (-5))
=-10/(-3)
= 10/3
So, now we plug that and one of the points, let's choose (-5,4), into
the equation:
y -4 = (10/3)(x- (-5))
y-4 =(10/3)(x +5)
3y-12= 10(x+5) (Multiply by 3)
3y -12 = 10x +50
-10x +3y = 50+12
-10x+3y =62
10x-3y = -62 (The first term must be positive.)
Hope this helps.
FE
how woul di find the standard form of the equation of the line that passes through the oints (-5, 4) and (-8, -6)
Standard form??
Hi,
In a few syllables: Use the point-slope form of a linear equation, which is this:
y -y1 = m(x-x1) (Where m is the slope and (x1,y1) is either of the two points. Here's how to use it:
1) First we need the slope:
m = (y2-y1)/(x2-x1) (We can choose either point as (x1,y1)
m = (-6 -4)/(-8- (-5))
=-10/(-3)
= 10/3
So, now we plug that and one of the points, let's choose (-5,4), into
the equation:
y -4 = (10/3)(x- (-5))
y-4 =(10/3)(x +5)
3y-12= 10(x+5) (Multiply by 3)
3y -12 = 10x +50
-10x +3y = 50+12
-10x+3y =62
10x-3y = -62 (The first term must be positive.)
Hope this helps.
FE
Standard form??
standard form is ax +by = c
so0o how do u write an equation in standard form for the line that contains each pair of points like:
1. (3,8), (6,4)
2. (-2, -1), (2,2)
Standard form??
find the slope (y2-y1)/(x2-x1)
(4-8)/(6-3) = -4/3
now pick a point to use (3,8)
and use point-slope y-y1 = m(x-x1)
y-8 = -4/3 (x-3)
clear the fraction by multiplying by 3
3y - 24 = -4x + 12
now get x and y on one side and everything else on the other
4x + 3y = 36
so0o how do u write an equation in standard form for the line that contains each pair of points like:
1. (3,8), (6,4)
2. (-2, -1), (2,2)
Standard form??
find the slope (y2-y1)/(x2-x1)
(4-8)/(6-3) = -4/3
now pick a point to use (3,8)
and use point-slope y-y1 = m(x-x1)
y-8 = -4/3 (x-3)
clear the fraction by multiplying by 3
3y - 24 = -4x + 12
now get x and y on one side and everything else on the other
4x + 3y = 36
Convert into Standard Form...Need help!!!?
I need to convert a slope-intercept form, y=2x+2, into a standard form. I know that Standard form is Ax+By=C, but I do not know how to convert the slope-intercept form into the standard form.
Please help
!!!!
Convert into Standard Form...Need help!!!?
All you have to do is use the addition and subtraction properties to move things around:
y=2x+2
Subtract 2x from both sides:
y-2x=2x-2x+2
Simplify:
y-2x=2
Use the commutative property (a+b=b+a)
-2x+y=2
Now it is standard form A=-2, B=1, C=2
Reply:This just means get x and y all on the left side.
So, subtract 2x from both sides of your equation. You'd get
-2x + y = 2 ... which is the answer.
Sometimes books require you to make "A" positive. If yours does, you just change the sign on everything. You'd get
2x - y = -2.
Please help
!!!!
Convert into Standard Form...Need help!!!?
All you have to do is use the addition and subtraction properties to move things around:
y=2x+2
Subtract 2x from both sides:
y-2x=2x-2x+2
Simplify:
y-2x=2
Use the commutative property (a+b=b+a)
-2x+y=2
Now it is standard form A=-2, B=1, C=2
Reply:This just means get x and y all on the left side.
So, subtract 2x from both sides of your equation. You'd get
-2x + y = 2 ... which is the answer.
Sometimes books require you to make "A" positive. If yours does, you just change the sign on everything. You'd get
2x - y = -2.
On a visit to Edinburgh, Scotland, I took a photo of a grave at Greyfriar's. Inscription: C.L. and only a year
I don't have the photo at the moment, as it's in another state, with other belongings, but the picture always haunted me. The grave was inconspicious, and I clearly remember the initials inscribed: C.L. and then the year, which I can't rightly recall, but it was either in the 1400's or 1500's. I am wondering if anyone who knows Scottish history could shed some light on why a headstone would only have intials and the year of death (I assume that's the year of death.). Could the person have been a criminal or an "undesirable"? I thought perhaps the person might have been homeless, without people knowing about their origins, but I gather that most people in that time era didn't go by initials. Perhaps this grave was a fluke, and I haven't been able to find out any info on a "C.L.". Was this a standard practice? I lived in the UK for several years and visited a lot of cemeteries in Ireland and the UK, and have yet to see another headstone with only initials.
On a visit to Edinburgh, Scotland, I took a photo of a grave at Greyfriar's. Inscription: C.L. and only a year
Possibly marking a child’s grave. Tell me where about in the cemetery it is %26amp; I will find out for you if I can.
Contact the City Council. Read this;
PRICELESS records of Edinburgh's rich past could be lost forever because of staff shortages and inadequate storage at the city archive, leading Scots historians have warned.
Thousands of artefacts, detailing the history of the capital from the tenth century to the present day, are kept beneath the City Chambers and in a warehouse at Murrayburn.
Among some of the unique items contained in the council-owned archive are the first recorded rules for playing golf, city records for criminal convictions, NOTES ON THE GRAVES within Greyfriars burial ground and records about the establishment of the Edinburgh Festival.
Reply:Greyfriars is supposedly haunted. Take a look at these sites, they will provide you with plenty of information....
http://www.google.com/search?sourceid=na...
Reply:The headstone would have been for someone of some importance although unfortunately I cannot help you find out what the initials CL stand for. This would not be a poor person or a criminal because such people would be buried in unmarked graves and it is unlikely that such people would be interred at Greyfriars.
Unfortunately, there has been a lot of vandalism at Greyfriars in recent years and this has included the destruction of headstones and the exhumation of bodies.
Reply:The cost of engraving may have had something to do with it.
hollyhock
On a visit to Edinburgh, Scotland, I took a photo of a grave at Greyfriar's. Inscription: C.L. and only a year
Possibly marking a child’s grave. Tell me where about in the cemetery it is %26amp; I will find out for you if I can.
Contact the City Council. Read this;
PRICELESS records of Edinburgh's rich past could be lost forever because of staff shortages and inadequate storage at the city archive, leading Scots historians have warned.
Thousands of artefacts, detailing the history of the capital from the tenth century to the present day, are kept beneath the City Chambers and in a warehouse at Murrayburn.
Among some of the unique items contained in the council-owned archive are the first recorded rules for playing golf, city records for criminal convictions, NOTES ON THE GRAVES within Greyfriars burial ground and records about the establishment of the Edinburgh Festival.
Reply:Greyfriars is supposedly haunted. Take a look at these sites, they will provide you with plenty of information....
http://www.google.com/search?sourceid=na...
Reply:The headstone would have been for someone of some importance although unfortunately I cannot help you find out what the initials CL stand for. This would not be a poor person or a criminal because such people would be buried in unmarked graves and it is unlikely that such people would be interred at Greyfriars.
Unfortunately, there has been a lot of vandalism at Greyfriars in recent years and this has included the destruction of headstones and the exhumation of bodies.
Reply:The cost of engraving may have had something to do with it.
hollyhock
Highest Standard Molar Entropy?
Which substance will have the highest standard molar entropy at 25°C?
A. C(graphite)
B. C2H4(g)
C. CH3OH(l)
D. MgCO3(s)
E. Cannot be determined
Highest Standard Molar Entropy?
B
A. C(graphite)
B. C2H4(g)
C. CH3OH(l)
D. MgCO3(s)
E. Cannot be determined
Highest Standard Molar Entropy?
B
Right now i am learning c.what next?
right now i am learning c.i am in 10 standard can somebody please help me to take a decision that what next should i learn
i want to make ,my carrer in computers .please help!!!!!!
Right now i am learning c.what next?
I would next pick up a good object-oriented language next. If you choose C# or Java the syntax will be similar to what you already know.
Reply:Good quesiton. To be honest, if you are ready for OOP and strongly typed languages II would go straight to C#. The advantages of going to next C# instead of C++:
-C# will keep you away from multiple inheritance
-C# (actually, the .NET Framework) has the garbage collector which will dispose of objects for you.
-C# is more type safe because in C++ you can still use ANSI C methods which aren't type safe (printf, macros)
-C# will prepare you for other modern OOP languages
-C# (to me) was easier to learn than C++
-C++ .NET will also help keep you away from the downfalls of regular ol' C++ but there isn't much books or documentation on the this version. That's fine if you already know C++ but I had some issues in which I had to rewrite some things that works fine in other .NET languages.
This is all squarely your decision. Check out all answers given and go with what you are comfortable with.
Reply:You should move onto Java and PHP and then start learning SQL, they are a good mix and there are plenty of jobs available in those areas.
Not sure where you're from but the site below is good for job hunting.
Reply:go with JAVA
Advantages of JAVA
Java has gained enormous popularity since it first appeared. Its rapid ascension and wide acceptance can be traced to its design and programming features, particularly in its promise that you can write a program once, and run it anywhere. Java was chosen as the programming language for network computers (NC) and has been perceived as a universal front end for the enterprise database. As stated in Java language white paper by Sun Microsystems: "Java is a simple, object-oriented, distributed, interpreted, robust, secure, architecture neutral, portable, multithreaded, and dynamic."
Reply:While you are on a winner stick with it.
Keep learning c until you can make it do handstands then there will always be work for you.
Reply:Finish up with C++, then C#. It wouldn't hurt to become involved with Microsoft Visual Studio.net 2005. There, with 1 IDE you can have Java, C++, C# and VisualBasic. The express editions are powerhouses, and they are free, as is SQL server express.
Reply:try going media. if ur good in design. photoshop flash and expression is good.
Reply:just dig it up the C language,it is mother of all language or apps
i want to make ,my carrer in computers .please help!!!!!!
Right now i am learning c.what next?
I would next pick up a good object-oriented language next. If you choose C# or Java the syntax will be similar to what you already know.
Reply:Good quesiton. To be honest, if you are ready for OOP and strongly typed languages II would go straight to C#. The advantages of going to next C# instead of C++:
-C# will keep you away from multiple inheritance
-C# (actually, the .NET Framework) has the garbage collector which will dispose of objects for you.
-C# is more type safe because in C++ you can still use ANSI C methods which aren't type safe (printf, macros)
-C# will prepare you for other modern OOP languages
-C# (to me) was easier to learn than C++
-C++ .NET will also help keep you away from the downfalls of regular ol' C++ but there isn't much books or documentation on the this version. That's fine if you already know C++ but I had some issues in which I had to rewrite some things that works fine in other .NET languages.
This is all squarely your decision. Check out all answers given and go with what you are comfortable with.
Reply:You should move onto Java and PHP and then start learning SQL, they are a good mix and there are plenty of jobs available in those areas.
Not sure where you're from but the site below is good for job hunting.
Reply:go with JAVA
Advantages of JAVA
Java has gained enormous popularity since it first appeared. Its rapid ascension and wide acceptance can be traced to its design and programming features, particularly in its promise that you can write a program once, and run it anywhere. Java was chosen as the programming language for network computers (NC) and has been perceived as a universal front end for the enterprise database. As stated in Java language white paper by Sun Microsystems: "Java is a simple, object-oriented, distributed, interpreted, robust, secure, architecture neutral, portable, multithreaded, and dynamic."
Reply:While you are on a winner stick with it.
Keep learning c until you can make it do handstands then there will always be work for you.
Reply:Finish up with C++, then C#. It wouldn't hurt to become involved with Microsoft Visual Studio.net 2005. There, with 1 IDE you can have Java, C++, C# and VisualBasic. The express editions are powerhouses, and they are free, as is SQL server express.
Reply:try going media. if ur good in design. photoshop flash and expression is good.
Reply:just dig it up the C language,it is mother of all language or apps
AP Chemistry or AP Physics C?
I'm an IB junior right now and we're registering for our senior classes soon. I have pretty much tweaked everything out for my IB requirements leaving one open class which i cannot decide between AP Chemistry or AP Physics C.
I'm taking IB standard level physics/ AP physics B right now and i have an A on an adjusted scale. I'm also taking Calculus AB right now so i'll be taking BC next year along with IB higher level math so there are no worries as to my math problem solving skills.
I REALLY REALLY like physics (and math), but seeing that i already have a physics credit, should i take chem instead? also, i took dinky IB chem for only a semester my sophomore year that means if i don't take chem next year, i'll be away from it for two years when entering college. But the thing is, i want to major in possibly mechanical or aeronautical engineering so physics C WOULD be the better choice..
I'm so confused!
AP Chemistry or AP Physics C?
You know, I'd probably go Chem. AP Chem crosses over some with AP Physics B and coming into college more than two years out of Chem, might make for a very difficult General Chem requirement.
Reply:I am a Senior not in IB and currently taking Chem AP and Physics B AP. Physics and Chemistry do overlap in some areas but since it's Physics C instead of B, there won't be much similarity. I would suggest taking AP Physics to show your dedication to colleges on how much you want to prepare for a mechanical or aeronautical engineering major. You are willing to take a step further and challenge yourself in a higher level physics course. Don't worry about being away from Chem for two years; Chem isn't as difficult as Physics ;) Maybe I'm biased because I %26lt;3 Physics. :)
Reply:Take the physics, as it has a broader application to all of the sciences. If you look at any collegiate-level science curriculum, regardless of the major, it will requires physics. Very few require chemistry.
I'm taking IB standard level physics/ AP physics B right now and i have an A on an adjusted scale. I'm also taking Calculus AB right now so i'll be taking BC next year along with IB higher level math so there are no worries as to my math problem solving skills.
I REALLY REALLY like physics (and math), but seeing that i already have a physics credit, should i take chem instead? also, i took dinky IB chem for only a semester my sophomore year that means if i don't take chem next year, i'll be away from it for two years when entering college. But the thing is, i want to major in possibly mechanical or aeronautical engineering so physics C WOULD be the better choice..
I'm so confused!
AP Chemistry or AP Physics C?
You know, I'd probably go Chem. AP Chem crosses over some with AP Physics B and coming into college more than two years out of Chem, might make for a very difficult General Chem requirement.
Reply:I am a Senior not in IB and currently taking Chem AP and Physics B AP. Physics and Chemistry do overlap in some areas but since it's Physics C instead of B, there won't be much similarity. I would suggest taking AP Physics to show your dedication to colleges on how much you want to prepare for a mechanical or aeronautical engineering major. You are willing to take a step further and challenge yourself in a higher level physics course. Don't worry about being away from Chem for two years; Chem isn't as difficult as Physics ;) Maybe I'm biased because I %26lt;3 Physics. :)
Reply:Take the physics, as it has a broader application to all of the sciences. If you look at any collegiate-level science curriculum, regardless of the major, it will requires physics. Very few require chemistry.
How do you calulate "C.V." (Coefficient of Variation) AT (<this is important) 90% confidence?
Typically, to calculate "C.V.", you divide the standard deviation by the mean...but I need to calculate "C.V." AT 90% confidence?!
How do you calulate "C.V." (Coefficient of Variation) AT (%26lt;this is important) 90% confidence?
If you give me the information you have, i might be able to figure it out for you. It's important to know the distribution so I can lead you in the right direction. If you made an edit... i'll check back.
cabbage
How do you calulate "C.V." (Coefficient of Variation) AT (%26lt;this is important) 90% confidence?
If you give me the information you have, i might be able to figure it out for you. It's important to know the distribution so I can lead you in the right direction. If you made an edit... i'll check back.
cabbage
There is no any Standard Deduction of 1,10,000 from Income (from Profession) Tax ? can I not get this ?...?
First I do again more clear things : I am as a consultant... i have apointment leter but no any written contract from my company, I don't get any pay slips, I get amount in bank a/c.
There is no any Standard Deduction of 1,10,000 from Income (from Profession) Tax ? can I not get this ?
... if any person earns only 20,000 in a whole year... then he comes under 'Below Poverty Line' ... It means the government will take Taxe from this poor person also ? !!!!!!!
And if it is not taxable then why one should deduct TDS on this amount (as my salary is 10,000 pm). ? He can deduct TDS only on 10,000 (@10.3%) isn't it ?
Is it Rule by Govrment to deduct TDS if income (from profession or any source) is not exeeds limit?
I am very confused on this matter Please explain this.
There is no any Standard Deduction of 1,10,000 from Income (from Profession) Tax ? can I not get this ?...?
First and foremost, In Income tax terms, you are not an employee of the company u r working for but a "FREELANCER" and in all such cases rules stipulates that TDS has to be deducted @ 10.30% u/s 194J of the IT Act 1961.
But that does not mean that even if ur TAXABLE INCOME is less than 1,10,000 u have to pay any tax !!
Just consider this "Deduction" as "advance to government" and at the end of year you can claim back/get refund of this "DEDUCTION" by filing the return. You will also get interest on the refund.
I hope this will clear all your doubts.
Further, there is no more the concept standard deduction now. And in your case (being a freelancer in income tax paralance) has many other advantages which a "SALARIED" person may not have.
CA. Deepak Bholusaria
Reply:If u have earned only Rs 20000 in whole year then as per ur question you have worked only 2 months ( Rs 10000 pm * 2 ).
you were free to work some where else for rest of 10 months. so no need to compare urself with BPL peoples. they work for whole year ( 12 months ) and yet not earn Rs 20000. hence they are considered in below poverty line . they need not pay taxes.
income from certain professional services is considered taxable and hence tds is required to be done on these incomes.
however if u are not earning above taxable income. you file ITR and get refund on "taxes" deducted of ur income
There is no any Standard Deduction of 1,10,000 from Income (from Profession) Tax ? can I not get this ?
... if any person earns only 20,000 in a whole year... then he comes under 'Below Poverty Line' ... It means the government will take Taxe from this poor person also ? !!!!!!!
And if it is not taxable then why one should deduct TDS on this amount (as my salary is 10,000 pm). ? He can deduct TDS only on 10,000 (@10.3%) isn't it ?
Is it Rule by Govrment to deduct TDS if income (from profession or any source) is not exeeds limit?
I am very confused on this matter Please explain this.
There is no any Standard Deduction of 1,10,000 from Income (from Profession) Tax ? can I not get this ?...?
First and foremost, In Income tax terms, you are not an employee of the company u r working for but a "FREELANCER" and in all such cases rules stipulates that TDS has to be deducted @ 10.30% u/s 194J of the IT Act 1961.
But that does not mean that even if ur TAXABLE INCOME is less than 1,10,000 u have to pay any tax !!
Just consider this "Deduction" as "advance to government" and at the end of year you can claim back/get refund of this "DEDUCTION" by filing the return. You will also get interest on the refund.
I hope this will clear all your doubts.
Further, there is no more the concept standard deduction now. And in your case (being a freelancer in income tax paralance) has many other advantages which a "SALARIED" person may not have.
CA. Deepak Bholusaria
Reply:If u have earned only Rs 20000 in whole year then as per ur question you have worked only 2 months ( Rs 10000 pm * 2 ).
you were free to work some where else for rest of 10 months. so no need to compare urself with BPL peoples. they work for whole year ( 12 months ) and yet not earn Rs 20000. hence they are considered in below poverty line . they need not pay taxes.
income from certain professional services is considered taxable and hence tds is required to be done on these incomes.
however if u are not earning above taxable income. you file ITR and get refund on "taxes" deducted of ur income
Write an equation of a line with x intercept 6 and y intercept 4. Final Answer in standard form.?
Write an equation of a line with x intercept 6 and y intercept 4. Write the final answer in standard form. (Ax + By = C)
I already know the answer is 2x+3y = 12, I'm just clueless as to how they got that answer (review book)
Write an equation of a line with x intercept 6 and y intercept 4. Final Answer in standard form.?
The line passes through (6, 0) and (0, 4),
m(slope) = (4 - 0)/(0 - 6) = -2/3
y = mx + c
y = (-2/3)x + 4
3y = -2x + 12
2x + 3y = 12
Reply:at the x intercept y = 0 and at the y intercept x = 0
therefore we have the points (6,0) and (0,4)
find the gradient between these two points..
rise/run = (0-4)/(6-0) = -2/3
therefore using for now the equation y = mx + c we have m = -2/3. substituting x = 0 gives y = c = 4.
we now have y = -2/3*x + 4
rearranging this becomes y + 2/3*x = 4
now mulitply through by 3 to get...
2x + 3y = 12 !!
I already know the answer is 2x+3y = 12, I'm just clueless as to how they got that answer (review book)
Write an equation of a line with x intercept 6 and y intercept 4. Final Answer in standard form.?
The line passes through (6, 0) and (0, 4),
m(slope) = (4 - 0)/(0 - 6) = -2/3
y = mx + c
y = (-2/3)x + 4
3y = -2x + 12
2x + 3y = 12
Reply:at the x intercept y = 0 and at the y intercept x = 0
therefore we have the points (6,0) and (0,4)
find the gradient between these two points..
rise/run = (0-4)/(6-0) = -2/3
therefore using for now the equation y = mx + c we have m = -2/3. substituting x = 0 gives y = c = 4.
we now have y = -2/3*x + 4
rearranging this becomes y + 2/3*x = 4
now mulitply through by 3 to get...
2x + 3y = 12 !!
Visual C++ and C++ questions?
Hi,
I'm a confused.
i want to learn C++ and I don't know where to start.
I have the following questions.
1. What is the difference between C++ and visual C++ ? Which one is the standard programming language ?
2. What book do you recommend to learn C++ for a beginner ?
3. What are other ways that I can learn C++ easier ?
Thank you
Visual C++ and C++ questions?
c++ and visual c++ are the same thing just that visual makes programming windows app easier (it's pampered).. use bloodshed c++ to learn http://www.bloodshed.net/devcpp.html
book, hmm, i dunno. i learned basic skills using "problem solving with c++" by savitch, the book is alright and will teach you the basic. also anything from o'rileys is pretty good.
checkout these websites http://www.cprogramming.com and http://www.cplusplus.com/ they both have great tutorials
perhaps you should take a course at a local community college.
to start i would get bloodshed and do these tutorails http://www.cprogramming.com/tutorial/les... hit next for the next lesson (bottom of page in red plain text, says "Next:" and what the next lesson is)
Reply:http://yepoocha.blogspot.com
might help Report It
Reply:1) C++ is a language. Visual C++ is Microsoft's C++ compiler. Asking the difference is like asking the difference between a car and a Ford.
2) Hands down, Accelerated C++ ( http://sc.tri-bit.com/Moo for the Amazon referral link.)
3) There really aren't any. C++ is a large language with many pitfalls. You need a good primer book. Be aware that most C++ primer books are utter crap; it's important to get the right one. Accelerated C++ (the link above) is an excellent starting point.
I'm a confused.
i want to learn C++ and I don't know where to start.
I have the following questions.
1. What is the difference between C++ and visual C++ ? Which one is the standard programming language ?
2. What book do you recommend to learn C++ for a beginner ?
3. What are other ways that I can learn C++ easier ?
Thank you
Visual C++ and C++ questions?
c++ and visual c++ are the same thing just that visual makes programming windows app easier (it's pampered).. use bloodshed c++ to learn http://www.bloodshed.net/devcpp.html
book, hmm, i dunno. i learned basic skills using "problem solving with c++" by savitch, the book is alright and will teach you the basic. also anything from o'rileys is pretty good.
checkout these websites http://www.cprogramming.com and http://www.cplusplus.com/ they both have great tutorials
perhaps you should take a course at a local community college.
to start i would get bloodshed and do these tutorails http://www.cprogramming.com/tutorial/les... hit next for the next lesson (bottom of page in red plain text, says "Next:" and what the next lesson is)
Reply:http://yepoocha.blogspot.com
might help Report It
Reply:1) C++ is a language. Visual C++ is Microsoft's C++ compiler. Asking the difference is like asking the difference between a car and a Ford.
2) Hands down, Accelerated C++ ( http://sc.tri-bit.com/Moo for the Amazon referral link.)
3) There really aren't any. C++ is a large language with many pitfalls. You need a good primer book. Be aware that most C++ primer books are utter crap; it's important to get the right one. Accelerated C++ (the link above) is an excellent starting point.
Standard emf and standard potential?
(a) Calculate G° for the following cell reaction.
Tl(s) | Tl^+(aq) || Pb^2+(aq) | Pb(s)
The G°f for Tl^+ (aq) is -32.4 kJ/mol.
(b) From G°, calculate the standard emf for the cell reaction.
(c) From this, determine the standard potential for the following reaction.
Tl^+ (aq) + e^- --%26gt; Tl(s)
phlox
Tl(s) | Tl^+(aq) || Pb^2+(aq) | Pb(s)
The G°f for Tl^+ (aq) is -32.4 kJ/mol.
(b) From G°, calculate the standard emf for the cell reaction.
(c) From this, determine the standard potential for the following reaction.
Tl^+ (aq) + e^- --%26gt; Tl(s)
phlox
Ax + By = C stand form (equation help please)?
w/e answer you get for Ax + By = C you have to
multiply the answer by the denominator if there is a fraction
multiply to make any decimals go away in the answer
and multiply the entire answer by -1 if the x is negative
now when you multiply the answer by -1 to make x positive, is that rule ONLY for Standard Form (ax+by=c) or is that a rule for ALL linear equations???????
Ax + By = C stand form (equation help please)?
It's only for standard form. In slope-intercept, sometimes the x's will be and SHOULD BE negative.
Reply:The multiplying part is only for standard form, because in the other equations you might want to have a negative X to make the equation work.
Thanks for letting me help
multiply the answer by the denominator if there is a fraction
multiply to make any decimals go away in the answer
and multiply the entire answer by -1 if the x is negative
now when you multiply the answer by -1 to make x positive, is that rule ONLY for Standard Form (ax+by=c) or is that a rule for ALL linear equations???????
Ax + By = C stand form (equation help please)?
It's only for standard form. In slope-intercept, sometimes the x's will be and SHOULD BE negative.
Reply:The multiplying part is only for standard form, because in the other equations you might want to have a negative X to make the equation work.
Thanks for letting me help
Thursday, July 30, 2009
How can I figure out the standard form of the equation of the line?
The two points are (-6,-2) and (6,-4) and the slope is -1/6. How can I put this in standard form Ax+By=C?
How can I figure out the standard form of the equation of the line?
Point-slope formula:
y-y1=m(x-x1)
y+2=-1/6(x+6)
y+2=-1/6x-1
y=-1/6x-3
In Standard form:
Multiply both sides by 6:
6(y)=6(-1/6x-3)
6y=-x-18
Add x from both sides:
x+6y=-18
Check:
-6+6(-2)=-18
-6-12=-18
-18=-18
6+6(-4)=-18
6-24=-18
-18=-18
I hope this helps!
Reply:You're welcome! Report It
Reply:First, determine the equation to be used. We can use y=mx+b where m is the slope and b is the y-intercept.
Second, use any of the two pairs of coordinate to determine the y-intercept. Since the two pairs lie on the same line, any of the two pairs can be used. Let us use (6, -4)
y = mx+b
substitute the values for y, x and m,
(-4) = (-1/6)(6) + b
multiply -1/6 and 6
(-4) = (-1) + b
b + (-1) = (-4)
by adding (+1) to both sides we have,
b = -4 + 1
b = -3
therefore the y-intercept is -3....
Third, to form the equation, plug in the values of m and b,
y = mx + b
y = (-1/6)x + (-3)
multiply both sides by 6 to change all the numerical coefficients to integers..
6y = -x + (-18)
by adding (+x) to both sides we have,
6y + x = -18
or by commutative property,
x+6y = -18
===========
to check, plug in the two pairs of coordinates to our equation,
using (-6, -2)
x + 6y = -18
(-6) + 6(-2) = -18
(-6) + (-12) = -18
-18 = -18 since both sides are equal, the equation is true for coordinates (-6, -2)
using (6, -4)
x + 6y = -18
(6) + 6(-4) = -18
6 + (-24) = -18
-18 = -18 since both sides are equal, the equation is true for coordinates (6, -4)
since the equation is true for both the given pairs of coordinates, then our equation is correct..
Reply:standard form is Y=mX + b where m = slope and b = Y intercept
plug your co-ords and slope in
(y-y1) = m(x-x1)
y-y1 = mx - mx1
y = mx - mx1 +y1
y = mx + (y1-mx1)
y = mx + b let b = (y1 - mx1)
Reply:y = ax + b
wher a is the slope
so y = -1/6 x + b
if y = -2 then x = -6 so replacing in the above equation
-2 = (-1/6)(-6) + b
-2 = 1 + b =%26gt; b=-3
the equation is y = -1/6x -3
checking we replace the coordinates of the point (6,-4) into the equation we just found
we get
y = (-1/6)(6) - 3 = -4 so it's OK
in the standard form we get
-1/6 x -y = 3
Reply:well for any line the equation should go like :
y = mx + c
if you have two known points, substitute with their values at the above equation and get m %26amp; c values
for the example given by you
the two points are (-6,-2), (6,-4)
substituting with the first points :
-2 = -6m + c ---(1)
substituting with the second point :
-4 = 6m + c ---(2)
now solve (1) %26amp; (2) simultaneously to get the values of m and c..
I'd rather adding them to each other, therefore;
-2-4 = -6m + c + 6m + c
-6 = 2c
c = -3
now you can substitute with the value of c at either (1) or (2) to get m in case you don't have it..but you already know it's -1/6
so the equation of the line should be
y = (-1/6) x - 3 (multiply the whole equation by 6)
6y = -x - 18
therefore
x + 6y = -18
How can I figure out the standard form of the equation of the line?
Point-slope formula:
y-y1=m(x-x1)
y+2=-1/6(x+6)
y+2=-1/6x-1
y=-1/6x-3
In Standard form:
Multiply both sides by 6:
6(y)=6(-1/6x-3)
6y=-x-18
Add x from both sides:
x+6y=-18
Check:
-6+6(-2)=-18
-6-12=-18
-18=-18
6+6(-4)=-18
6-24=-18
-18=-18
I hope this helps!
Reply:You're welcome! Report It
Reply:First, determine the equation to be used. We can use y=mx+b where m is the slope and b is the y-intercept.
Second, use any of the two pairs of coordinate to determine the y-intercept. Since the two pairs lie on the same line, any of the two pairs can be used. Let us use (6, -4)
y = mx+b
substitute the values for y, x and m,
(-4) = (-1/6)(6) + b
multiply -1/6 and 6
(-4) = (-1) + b
b + (-1) = (-4)
by adding (+1) to both sides we have,
b = -4 + 1
b = -3
therefore the y-intercept is -3....
Third, to form the equation, plug in the values of m and b,
y = mx + b
y = (-1/6)x + (-3)
multiply both sides by 6 to change all the numerical coefficients to integers..
6y = -x + (-18)
by adding (+x) to both sides we have,
6y + x = -18
or by commutative property,
x+6y = -18
===========
to check, plug in the two pairs of coordinates to our equation,
using (-6, -2)
x + 6y = -18
(-6) + 6(-2) = -18
(-6) + (-12) = -18
-18 = -18 since both sides are equal, the equation is true for coordinates (-6, -2)
using (6, -4)
x + 6y = -18
(6) + 6(-4) = -18
6 + (-24) = -18
-18 = -18 since both sides are equal, the equation is true for coordinates (6, -4)
since the equation is true for both the given pairs of coordinates, then our equation is correct..
Reply:standard form is Y=mX + b where m = slope and b = Y intercept
plug your co-ords and slope in
(y-y1) = m(x-x1)
y-y1 = mx - mx1
y = mx - mx1 +y1
y = mx + (y1-mx1)
y = mx + b let b = (y1 - mx1)
Reply:y = ax + b
wher a is the slope
so y = -1/6 x + b
if y = -2 then x = -6 so replacing in the above equation
-2 = (-1/6)(-6) + b
-2 = 1 + b =%26gt; b=-3
the equation is y = -1/6x -3
checking we replace the coordinates of the point (6,-4) into the equation we just found
we get
y = (-1/6)(6) - 3 = -4 so it's OK
in the standard form we get
-1/6 x -y = 3
Reply:well for any line the equation should go like :
y = mx + c
if you have two known points, substitute with their values at the above equation and get m %26amp; c values
for the example given by you
the two points are (-6,-2), (6,-4)
substituting with the first points :
-2 = -6m + c ---(1)
substituting with the second point :
-4 = 6m + c ---(2)
now solve (1) %26amp; (2) simultaneously to get the values of m and c..
I'd rather adding them to each other, therefore;
-2-4 = -6m + c + 6m + c
-6 = 2c
c = -3
now you can substitute with the value of c at either (1) or (2) to get m in case you don't have it..but you already know it's -1/6
so the equation of the line should be
y = (-1/6) x - 3 (multiply the whole equation by 6)
6y = -x - 18
therefore
x + 6y = -18
Hepatitis c?
recently me and someone have been arguing about the hepatitis's there is your standard A B and C but is there different levels of the C? If so which level is the worst?
Hepatitis c?
This is what I got from Ask.com It directed me to the website below.
Q. What Are the Different Types of Hepatitis?
From National Women's Health Information Center
About.com Health's Disease and Condition content is reviewed by Steven Gans, MD
A. There are 5 types of hepatitis - A, B, C, D, and E - each caused by a different hepatitis virus.
Hepatitis A is caused by eating food and drinking water infected with a virus called HAV. It can also be caused by anal-oral contact during sex. While it can cause swelling and inflammation in the liver, it doesn't lead to chronic, or life long, disease. Almost everyone who gets hepatitis A has a full recovery.
Hepatitis B is caused by the virus HBV. It is spread by contact with an infected person's blood, semen, or other body fluid. And, it is a sexually transmitted disease (STD). You can get hepatitis B by:
Having unprotected sex (not using a condom) with an infected person.
Sharing drug needles (for illegal drugs like heroin and cocaine or legal drugs like vitamins and steroids).
Getting a tattoo or body piercing with dirty (unsterile) needles and tools that were used on someone else.
Getting pricked with a needle that has infected blood on it (health care workers can get hepatitis B this way).
Sharing a toothbrush, razor, or other personal items with an infected person.
An infected woman can give hepatitis B to her baby at birth or through her breast milk.
Through a bite from another person.
With hepatitis B, the liver also swells. Hepatitis B can be a serious infection that can cause liver damage, which may result in cancer. Some people are not able to get rid of the virus, which makes the infection chronic, or life long. Blood banks test all donated blood for hepatitis B, greatly reducing the risk for getting the virus from blood transfusions or blood products.
Hepatitis C is caused by the virus HCV. It is spread the same way as hepatitis B, through contact with an infected person's blood, semen, or body fluid (see above). Like hepatitis B, hepatitis C causes swelling of the liver and can cause liver damage that can lead to cancer. Most people who have hepatitis C develop a chronic infection. This may lead to a scarring of the liver, called cirrhosis. Blood banks test all donated blood for hepatitis C, greatly reducing the risk for getting the virus from blood transfusions or blood products.
Hepatitis D is caused by the virus HDV. You can only get hepatitis D if you are already infected with hepatitis B. It is spread through contact with infected blood, dirty needles that have HDV on them, and unprotected sex (not using a condom) with a person infected with HDV. Hepatitis D causes swelling of the liver.
Hepatitis E is caused by the virus HEV. You get hepatitis E by drinking water infected with the virus. This type of hepatitis doesn't often occur in the U.S. It causes swelling of the liver, but no long-term damage. It can also be spread through oral-anal contact.
Sponsored Links
Hepatitis Symptoms
Find Symptoms of Hepatitis Info for Hepatitis Types A - C
hepatitis-symptoms-web.com
Hepatitis
A complete website dedicated to Hepatitis
www-Hepatitis.net
Reply:You may be referring to genotypes of HCV - there are genotypes 1 to 6 with 5 substypes a,b,c,d,e
Most people in the US have 1a or 1b.
Genotypes 2 and 3 are usually in Europe and Asia.
Genotype 1's require a longer treatment schedule of 48 weeks instead of the 24 week schedule for Genotypes 2 and 3.
I had 1b, so I had to do the 48 week treatment...all better now!
Reply:The different levels are actually called genotypes.
there are 1a,1b,1c,1d,1,e, 2a, 2b, 2c and so forth.
Any genotype can be bad. The difference between 1a, 1b's and 4's are that they are harder to treat than the other genotypes.
I know many who didn't have the harder to treat genotypes yet their quality of life was low. I know some that have the hard to treat genotypes and they seem to be doing well. So, in all reality, any hcv genotypes can be bad. The degree of symptoms do not always correlate with the level of virons nor liver disease.
I'm a 2b (cured with antiviral chemotherapy post 5 years) but my quality of life was aweful until treatment. My liver damage was only a 2.1. (now a 1.1.) yet the symptoms were horrible.
I know those that have 1a or 1b and even tho their liver damage is bad, they have less symptoms....
It's real complex because a lot of heppers have so many different things wrong with them (bi-directional diseases). It depends on lifestyle too. What we eat and drink ect has a direct impact on our health.
I did something right for 26 or so years-i limited my intake of otc meds and even prescription meds. I did not tolerate alcohol all that well ever, but really dont care to drink anyway.
Each genotype can be no more nor no less worse than the other. Again, the difference is response rates to the only well known and studied treatment and that is antiviral chemotherapy. Again 1's and 4's are harder to treat.
Reply:There is only one hep C. It can lay dormit in the body for many years. Each person can have a different pattern of the same disease.
Hepatitis c?
This is what I got from Ask.com It directed me to the website below.
Q. What Are the Different Types of Hepatitis?
From National Women's Health Information Center
About.com Health's Disease and Condition content is reviewed by Steven Gans, MD
A. There are 5 types of hepatitis - A, B, C, D, and E - each caused by a different hepatitis virus.
Hepatitis A is caused by eating food and drinking water infected with a virus called HAV. It can also be caused by anal-oral contact during sex. While it can cause swelling and inflammation in the liver, it doesn't lead to chronic, or life long, disease. Almost everyone who gets hepatitis A has a full recovery.
Hepatitis B is caused by the virus HBV. It is spread by contact with an infected person's blood, semen, or other body fluid. And, it is a sexually transmitted disease (STD). You can get hepatitis B by:
Having unprotected sex (not using a condom) with an infected person.
Sharing drug needles (for illegal drugs like heroin and cocaine or legal drugs like vitamins and steroids).
Getting a tattoo or body piercing with dirty (unsterile) needles and tools that were used on someone else.
Getting pricked with a needle that has infected blood on it (health care workers can get hepatitis B this way).
Sharing a toothbrush, razor, or other personal items with an infected person.
An infected woman can give hepatitis B to her baby at birth or through her breast milk.
Through a bite from another person.
With hepatitis B, the liver also swells. Hepatitis B can be a serious infection that can cause liver damage, which may result in cancer. Some people are not able to get rid of the virus, which makes the infection chronic, or life long. Blood banks test all donated blood for hepatitis B, greatly reducing the risk for getting the virus from blood transfusions or blood products.
Hepatitis C is caused by the virus HCV. It is spread the same way as hepatitis B, through contact with an infected person's blood, semen, or body fluid (see above). Like hepatitis B, hepatitis C causes swelling of the liver and can cause liver damage that can lead to cancer. Most people who have hepatitis C develop a chronic infection. This may lead to a scarring of the liver, called cirrhosis. Blood banks test all donated blood for hepatitis C, greatly reducing the risk for getting the virus from blood transfusions or blood products.
Hepatitis D is caused by the virus HDV. You can only get hepatitis D if you are already infected with hepatitis B. It is spread through contact with infected blood, dirty needles that have HDV on them, and unprotected sex (not using a condom) with a person infected with HDV. Hepatitis D causes swelling of the liver.
Hepatitis E is caused by the virus HEV. You get hepatitis E by drinking water infected with the virus. This type of hepatitis doesn't often occur in the U.S. It causes swelling of the liver, but no long-term damage. It can also be spread through oral-anal contact.
Sponsored Links
Hepatitis Symptoms
Find Symptoms of Hepatitis Info for Hepatitis Types A - C
hepatitis-symptoms-web.com
Hepatitis
A complete website dedicated to Hepatitis
www-Hepatitis.net
Reply:You may be referring to genotypes of HCV - there are genotypes 1 to 6 with 5 substypes a,b,c,d,e
Most people in the US have 1a or 1b.
Genotypes 2 and 3 are usually in Europe and Asia.
Genotype 1's require a longer treatment schedule of 48 weeks instead of the 24 week schedule for Genotypes 2 and 3.
I had 1b, so I had to do the 48 week treatment...all better now!
Reply:The different levels are actually called genotypes.
there are 1a,1b,1c,1d,1,e, 2a, 2b, 2c and so forth.
Any genotype can be bad. The difference between 1a, 1b's and 4's are that they are harder to treat than the other genotypes.
I know many who didn't have the harder to treat genotypes yet their quality of life was low. I know some that have the hard to treat genotypes and they seem to be doing well. So, in all reality, any hcv genotypes can be bad. The degree of symptoms do not always correlate with the level of virons nor liver disease.
I'm a 2b (cured with antiviral chemotherapy post 5 years) but my quality of life was aweful until treatment. My liver damage was only a 2.1. (now a 1.1.) yet the symptoms were horrible.
I know those that have 1a or 1b and even tho their liver damage is bad, they have less symptoms....
It's real complex because a lot of heppers have so many different things wrong with them (bi-directional diseases). It depends on lifestyle too. What we eat and drink ect has a direct impact on our health.
I did something right for 26 or so years-i limited my intake of otc meds and even prescription meds. I did not tolerate alcohol all that well ever, but really dont care to drink anyway.
Each genotype can be no more nor no less worse than the other. Again, the difference is response rates to the only well known and studied treatment and that is antiviral chemotherapy. Again 1's and 4's are harder to treat.
Reply:There is only one hep C. It can lay dormit in the body for many years. Each person can have a different pattern of the same disease.
4/v = (v - 6) / (v - 4), standard form?
How do I get it in standard form, ax+bx+c = 0, so I can do the quadratic formula?
4/v = (v - 6) / (v - 4), standard form?
Just cross multiply here.
4*(v-4) = (v-6)*v
4v - 16 = v² - 6v
0 = v² - 10v + 16 ---%26gt;"standard form"
Factor way to solve:
0 = v² - 10v + 16
0 = (v - 2)(v - 8)
0 = v-2, and 0 = v-8
v = 2, and v = 8
Or use quadratic formula:
v = [-b ± √(b² - 4ac)] / 2a
v = [10 ± √(10² - 4(1)(16))] / 2(1)
v = [10 ± √(100 - 64)] / 2
v = [10 ± √(36)] / 2
v = [10 ± 6] / 2
So, 2 answers:
v = (10+6)/2, and v = (10-6)/2
v = 16/2, and v = 4/2
v = 8, and v = 2
Reply:Simplifyin it......
4v - 16 = v^2 -6v
v^2 -10v + 16 =0
v=8 or v=2.
sol set { 8 or 2}
Reply:4/v = (v - 6)/(v - 4)
4(v - 4) = v(v - 6)
4v - 16 = v^2 - 6v
v^2 - 10v + 16 = 0
The equation is now in the form ax^2 + bx + c, you can either use fatorisation, completing the square or quadratic formula. However, factorisation is more preferred in solving this equation.
(v - 2)(v - 8) = 0
v = 2 or v = 8
Reply:4/v = (v-6) / (v-4)
4 = (v-6) / (v-4) * v
4 = (v2 -6v -4v + 24) * v
4 = v3 - 10v2 + 24v
0 = v3 - 10v2 + 24v - 4
Reply:v^2-10v+16=0
verbena
4/v = (v - 6) / (v - 4), standard form?
Just cross multiply here.
4*(v-4) = (v-6)*v
4v - 16 = v² - 6v
0 = v² - 10v + 16 ---%26gt;"standard form"
Factor way to solve:
0 = v² - 10v + 16
0 = (v - 2)(v - 8)
0 = v-2, and 0 = v-8
v = 2, and v = 8
Or use quadratic formula:
v = [-b ± √(b² - 4ac)] / 2a
v = [10 ± √(10² - 4(1)(16))] / 2(1)
v = [10 ± √(100 - 64)] / 2
v = [10 ± √(36)] / 2
v = [10 ± 6] / 2
So, 2 answers:
v = (10+6)/2, and v = (10-6)/2
v = 16/2, and v = 4/2
v = 8, and v = 2
Reply:Simplifyin it......
4v - 16 = v^2 -6v
v^2 -10v + 16 =0
v=8 or v=2.
sol set { 8 or 2}
Reply:4/v = (v - 6)/(v - 4)
4(v - 4) = v(v - 6)
4v - 16 = v^2 - 6v
v^2 - 10v + 16 = 0
The equation is now in the form ax^2 + bx + c, you can either use fatorisation, completing the square or quadratic formula. However, factorisation is more preferred in solving this equation.
(v - 2)(v - 8) = 0
v = 2 or v = 8
Reply:4/v = (v-6) / (v-4)
4 = (v-6) / (v-4) * v
4 = (v2 -6v -4v + 24) * v
4 = v3 - 10v2 + 24v
0 = v3 - 10v2 + 24v - 4
Reply:v^2-10v+16=0
verbena
The electrode potential of the standard hydrogen electrode is 0.00 V. How is this potential determined?
a Any value could be chosen; 0.00 V is assigned for convenience.
b By comparison with the standard Ag | Ag+ electrode.
c By measuring the potential at different atmospheric pressures.
d By measuring the potential at different H+ concentrations.
The electrode potential of the standard hydrogen electrode is 0.00 V. How is this potential determined?
a.
b By comparison with the standard Ag | Ag+ electrode.
c By measuring the potential at different atmospheric pressures.
d By measuring the potential at different H+ concentrations.
The electrode potential of the standard hydrogen electrode is 0.00 V. How is this potential determined?
a.
Algebra Assistance - Converting an equation in Slope Intercept Form to standard form?
I have an equation of the form y=1/4x-2 I must convert this into standard form with only intergers and a positive coefficient for x.
I don't understand how to convert my answer which has a negative coefficient in the standard form Ax+By=c
Here is what I arrived at:
-1x+4y=-8
I don't know how to get rid of the -1 and keep the standard form.
I'm sure its simple but need a little direction.
;)
Algebra Assistance - Converting an equation in Slope Intercept Form to standard form?
Your close, you have to multiply the equation you have by -1 like this:
-1x+4y=-8
1x-4y=8 You just have to make everything the opposite of what it was before
I don't understand how to convert my answer which has a negative coefficient in the standard form Ax+By=c
Here is what I arrived at:
-1x+4y=-8
I don't know how to get rid of the -1 and keep the standard form.
I'm sure its simple but need a little direction.
;)
Algebra Assistance - Converting an equation in Slope Intercept Form to standard form?
Your close, you have to multiply the equation you have by -1 like this:
-1x+4y=-8
1x-4y=8 You just have to make everything the opposite of what it was before
How do I write the standard equation of a line?!?
I need to write line equations using the standard form Ax+By=C. I know the Point-Slope form and Slope intercept form but I don't know how to change it into the Standard form.
How do I write the standard equation of a line?!?
Here's an example.
This is point slope form: y=2x+3
To change it to standard form, just subtract the y from both sides to get 0=2x-y+3.
Then subtract the three from both sides to get 2x-y=3, and that's your answer!
How do I write the standard equation of a line?!?
Here's an example.
This is point slope form: y=2x+3
To change it to standard form, just subtract the y from both sides to get 0=2x-y+3.
Then subtract the three from both sides to get 2x-y=3, and that's your answer!
Assume that x has a normal distribution, with the specified mean and standard deviation.?
Assume that x has a normal distribution, with the specified mean and standard deviation. I need to find the indicated probabilities;
a)P(40%26lt;X%26lt;47); mean=50; standard deviation=15
b)P(X%26gt;2); mean=3; standard deviation=0.25
c)Find z such that 97.5% of the standard normal curve lies to the left of z
d)Find z such that 95% of the standard normal curve lies to the right of z
Assume that x has a normal distribution, with the specified mean and standard deviation.?
For any normal random variable X with mean μ and standard deviation σ, X ~ Normal(μ, σ)
you can translate into standard normal units by:
Z = (X - μ) / σ
where Z ~ Normal(μ = 0, σ = 1). You can then use the standard normal cdf tables to get probabilities.
a)
X ~ Normal(μ = 50, σ = 15)
P( 40 %26lt; X %26lt; 47 )
= P( (40 - 50) / 15 %26lt; Z %26lt; (47 - 50) / 15)
= P( - 2/3 %26lt; Z %26lt; - 1/5)
= P( Z %26lt; - 1/5) - P( Z %26lt; - 2.3)
= 0.4207403 - 0.2524925
= 0.1682478
---------
b)
X ~ Normal(μ = 3, σ = 0.25)
P( X %26gt; 2)
= P(Z %26gt; (2 -3 ) / 0.25)
= P( Z %26gt; -4)
= 0.9999683
----------
c)
P( Z %26lt; z ) = 0.975
z = 1.96
------------------
d)
P(Z %26gt; z) = 0.95
z = -1.645
Reply:You need a table for that..look at the back of your book..
snapdragon2
a)P(40%26lt;X%26lt;47); mean=50; standard deviation=15
b)P(X%26gt;2); mean=3; standard deviation=0.25
c)Find z such that 97.5% of the standard normal curve lies to the left of z
d)Find z such that 95% of the standard normal curve lies to the right of z
Assume that x has a normal distribution, with the specified mean and standard deviation.?
For any normal random variable X with mean μ and standard deviation σ, X ~ Normal(μ, σ)
you can translate into standard normal units by:
Z = (X - μ) / σ
where Z ~ Normal(μ = 0, σ = 1). You can then use the standard normal cdf tables to get probabilities.
a)
X ~ Normal(μ = 50, σ = 15)
P( 40 %26lt; X %26lt; 47 )
= P( (40 - 50) / 15 %26lt; Z %26lt; (47 - 50) / 15)
= P( - 2/3 %26lt; Z %26lt; - 1/5)
= P( Z %26lt; - 1/5) - P( Z %26lt; - 2.3)
= 0.4207403 - 0.2524925
= 0.1682478
---------
b)
X ~ Normal(μ = 3, σ = 0.25)
P( X %26gt; 2)
= P(Z %26gt; (2 -3 ) / 0.25)
= P( Z %26gt; -4)
= 0.9999683
----------
c)
P( Z %26lt; z ) = 0.975
z = 1.96
------------------
d)
P(Z %26gt; z) = 0.95
z = -1.645
Reply:You need a table for that..look at the back of your book..
snapdragon2
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