Saturday, May 22, 2010

Standard Free energy?

Calculate standard free energy of formation of 1 mol FeS2 at 25 degree's C





Fe(s) + 2S(s) %26lt;-------%26gt; FeS2(s)





For Fe at 25 degrees C, Delta S = 27.3 J/mol x K


For S at 25 degrees C, Delta S= 31.8 J/mol x K





for FeS2 at 25 degrees


delta S=52.9 J/mol x K and delta H= -178.2 kJ/mol





a–1.9 × 105 J/mol


b–1.8 × 105 J/mol


c–38 J/mol


d–1.7 × 105 J/mol

Standard Free energy?
d

rosemary

No comments:

Post a Comment