How do you find slope given an equation in standard form?

Standard form is Ax+By=C


I have 4x+3y=2


How do I find the slope?

How do you find slope given an equation in standard form?
The slope of ANY equation written in standard form is -A/B. Your teacher probably didn't tell you this so now you can amaze him when he sees how fast you can find the slope.





So in this equation, A = 4, B = 3. Plug it in, and you will get -(4/3).
Reply:You will need to graph it first





y2-y1/x2-x1
Reply:Rearrange.





4x + 3y = 2 (The actual equation)


3y = -4x + 2 (add 4x)


y = -4/3x +2/3 (divide by 3)





The slope is -4/3
Reply:You put that equation in slope-form intercept (y=mx+b).Solve for y in other words


4x+3y=2 First you minus 4x by both sides


-4x___-4x Then divide 3 by both sides to get y by


3y= -4x+2 Itself


3 3


y= -4/3x+2





x is the slope which is -4/3
Reply:-A/B
Reply:Slope is -4/3, I think.





A slope formula we were tought is y=mx + b where m always stands for slope. In this case, I transformed the formula Ax+By=C into By= -Ax+C. Since you need to get rid of the numerical coefficient of y, transpose B by dividing both sides by it.





From 3y= -4x+2, it will now look like y=(-4x+2)/3 or y=(-4x)/3 + 2/3 in simplest form. Since the slope is the numerical coefficient of x, -4/3 will then be the slope.
Reply:The easiest way to remember what to do is just to remember that the slope is the y-intercept
Reply:4x + 3y = 2


y = -4/3 x + 2/3





the equation is y = mx + b; where m is the slope..


therefore, -4/3 is your slope...