Thursday, July 30, 2009

Mean, range and standard deviation?

consider the following list of high temperature recorded in Nome, Alaska the last 12 days of december, 2003.





2, 4, -3, 8, -6, 7, 0, -4, 8, 7, 5, 3





a) what is the mean?


b) what is the range?


c) what is the standard deviation?





thank you

Mean, range and standard deviation?
2, 4, -3, 8, -6, 7, 0, -4, 8, 7, 5, 3





a) what is the mean?


add them up divide the number of observations,


30.996/12 = 2.583





b) what is the range?


I guess you want the plot box,


Minimum = -6


Q1 = -1.5


Med = 3.5


Q3 = 7


Maximum = 8


I have the data as -6, -4, -3, 0 , 2, 3 , 4, 5 , 7, 7, 8, 8





c) what is the standard deviation?


average is 2.583, use individual data minus average you have


-8.583, -6.583, -5.583, -2.583, -0.583, 0.417, 1.417, 2.417, 4.417, 4.417, 5.417, 5.417,





square each of them, 73.668, 43.34, 31.17, 6.67, 0.3399, 0.174, 2.0079, 5.84, 19.51, 19.51, 29.34, 29.34,





Add them up, about 260.91.





260.91/n-1 , n is number of observations, which is 12 here.


260.91/11 = 23.719





square root of this value:


sqrt of 23.719 = 4.870





Standard deviation = 4.870








*still confused? write back


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