A gas has a pressure of 0.370 atm at 50.0 °C. What is the pressure at standard temperature?
What is the pressure at standard temperature?
the equation is (starting pressure)/(starting temperature) = (ending pressure)/(ending temperature)
Substitute in:
0.370 atm / 323 K = X atm / 273 K, where X is ending pressure
0.370 atm * 273 K / 323 K = X atm
0.313 atm = X (ending pressure)
Reply:Gay Lussac's Law.
"The absolute pressure of a given mass of gas is directly proportional to is temperature at constant volume".
P1T2 = P2T1
P1 = 0.370atm...T2 = 273K
P2 = ?...............T1 = 323K
P2 = (0.370 x 273) ÷ 323
P2 = 101.01 ÷ 323
P2 = 0.313atm = Final pressure.
Reply:Do your own homework.
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