How do you go from standard form of an ellipse or hyperbola to the Ax^2+By^2=C?

This is for trigonometry I can get the standard form but can't transform it.

How do you go from standard form of an ellipse or hyperbola to the Ax^2+By^2=C?
A*x^2+B*y2^=C


First we divide with C and get


x^2*A/C+y^2*B/C=1%26lt;=%26gt;


x^2/(C/A)+y^2/(C/B)=1%26lt;=%26gt;


x^2/[sqrt(C/A)]^2 + y^2^/[sqrt(C/B)]^2 =1


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Now you have the length of Majoraxis Ama


Ama = 2*sqrt(C/A)


and the length of Minoraxis Ami = 2*sqrt(C/b)
Reply:(A/C)x^2 +- (B/C)y^2 = 1





just divide out the factor ....the denominator sets up the major %26amp; minor axis..








as an example....


4x^2 + 2y^2 = 16


(1/4) X^2 + (1/8) Y^2 = 1 ( sum = ellipse)





major axis = y ...... root(8) = 2 root(2)


minor axis = x ...... root(4) = 2