1) x^2 = -6 - 5x
2) 2x + 15 = x^2
3) y^2 - 7y + 6= -4
4) 3x = 2 - 2x^3
Rearrange the terms of each equation to put it in standard quadratic form:ax^2+bx+c=0.?
just add or subtract the numbers on one side of the equation to get 0 on that side.
1) x^2 = -6 - 5x.
You need one side to be 0, so subtract the numbers from that side. Let's make the right side 0.
x^2 = -6 - 5x --%26gt;
x^2 + 5x = -6 - 5x + 5x --%26gt;
x^2 + 5x = -6 --%26gt;
x^2 + 5x + 6 = -6 + 6 --%26gt;
x^2 + 5x + 6 = 0!
you do the same thing for every problem.
Good luck!
Reply:1) add the 6 and 5
x^2+5x+6
2) subtract 2x and 15 [easier to have these negative]
x^2-2x-15
3) add the 4
y^2-7y+10
4) add 2x^3 and subtract 2
2x^3+3x-2
Reply:I'm not doing your hw for you now if you don't know how to do it I will show you just mail me sportzgirl25@verizon.net
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