Sn2+ + 2e- ---%26gt; Sn Eo = -0.14 V
Cu2+ + 2e- ---%26gt; Cu Eo = +0.34 V
In a galvanic cell, the voltage is positve. So, reverse the first equation and add to the second to get a positive emf.
Sn ---%26gt; Sn2+ + 2e- Eo = +0.14 V
Cu2+ + 2e- ---%26gt; Cu Eo = +0.34 V
Overall reaction:
Sn + Cu2+ ---%26gt; Sn2+ + Cu Eo(cell) = +0.48 V
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