2.5x - .3 /3 =1/6 y write this equation in standard form identify a, b, and c?

Ax +By = C is standard form...A,B,C are NOT FRACTIONS OR DECIMALS


2.5x/3 -.3/3 = 1/6 y


first lets fix up .3/3 that = .1


and 2.5x/3 = 25x/30= 5x/6....don't put as decimal because it's repeating


so 5x/6 -.1 = 1/6y


now lets get rid of the fraction....multiply every term by 6


6*5x/6 -6*.1 = 6*1/6y


5x - .6 = y


now lets get rid of the decimal by multiplying every term by 10


10*5x -10*.6 = 10*y


50x -6 = 10y


now lets put the x and y on one side and the constant on the other side


usually ax is preferred to be positive so I am going to move the 10y and the -6 by subtracting 10y from both sides and adding 6 to both sides


50x -6 = 10 y


........+6...........+6


50x ............= 10y +6


........-10y........-10y


50x -10y = 6


finally in standard form


so A=50 , B= -10 and C= 6





There are other orders you could have taken but this way definately works.....

2.5x - .3 /3 =1/6 y write this equation in standard form identify a, b, and c?
7.5x -0.3 = 0.5y


75x - 5y =3


a= 75.


b=5


c=3
Reply:I think you mean (2.5 x - .3)/3 = 1/6 y...





so mulitply the equation by 3...





2.5 x -.3 = 1/2y





then convert to... (subtract each side by 1/2 y and add .3 to each side)





standard form: 2.5x -1/2y = .3





a= 2.5


b= -1/2


c= .3





Hope this helps.

gifts